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  • This right here is a picture of an Airbus A380 aircraft.

  • And I was curious how long would it

  • take this aircraft to take off?

  • And I looked up its takeoff velocity.

  • And the specs I got were 280 kilometers per hour.

  • And to make this a velocity we have to specify a direction as

  • well, not just a magnitude.

  • So the direction is in the direction of the runway.

  • So that would be the positive direction right over there.

  • So when we're talking about acceleration or velocity

  • in this, we're going to assume it's

  • in this direction, the direction of going down the runway.

  • And I also looked up its specs, and this,

  • I'm simplifying a little bit, because it's not

  • going to have a purely constant acceleration.

  • But let's just say from the moment

  • that the pilot says we're taking off to when it actually

  • takes off it has a constant acceleration.

  • Its engines are able to provide a constant acceleration

  • of 1.0 meters per second per second.

  • So after every second it can go one meter per second

  • faster than it was going at the beginning of that second.

  • Or another way to write this is 1.0-- let me write it

  • this way-- meters per second per second

  • can also be written as meters per second squared.

  • I find this a little bit more intuitive.

  • This is a little bit neater to write.

  • So let's figure this out.

  • So the first thing we're trying to answer

  • is, how long does take off last?

  • That is the question we will try to answer.

  • And to answer this, at least my brain

  • wants to at least get the units right.

  • So over here we have our acceleration

  • in terms of meters and seconds, or seconds squared.

  • And over here we have our takeoff velocity

  • in terms of kilometers and hours.

  • So let's just convert this takeoff velocity

  • into meters per second.

  • And then it might simplify answering this question.

  • So if we have 280 kilometers per hour,

  • how do we convert that to meters per second?

  • So let's convert it to kilometers per second first.

  • So we want to get rid of this hours.

  • And the best way to do that, if we

  • have an hour in the denominator, we

  • want an hour in the numerator, and we

  • want a second in the denominator.

  • And so what do we multiply this by?

  • Or what do we put in front of the hours and seconds?

  • So one hour, in one hour there are 3,600 seconds,

  • 60 seconds in a minute, 60 minutes in an hour.

  • And so you have one of the larger unit

  • is equal to 3,600 of the smaller unit.

  • And that we can multiply by that.

  • And if we do that, the hours will cancel out.

  • And we'll get 280 divided by 3,600 kilometers per second.

  • But I want to do all my math at once.

  • So let's also do the conversion from kilometers to meters.

  • So once again, we have kilometers in the numerator.

  • So we want the kilometers in the denominator now.

  • So it cancels out.

  • And we want meters in the numerator.

  • And what's the smaller unit?

  • It's meters.

  • And we have 1,000 meters for every 1 kilometer.

  • And so when you multiply this out the kilometers

  • are going to cancel out.

  • And you are going to be left with 280 times 1,

  • so we don't have to write it down, times 1,000,

  • all of that over 3,600, and the units we have left

  • are meters per-- and the only unit we have left here

  • is second-- meters per second.

  • So let's get my trusty TI-85 out and actually calculate this.

  • So we have 280 times 1000, which is obviously 280,000, but let

  • me just divide that by 3,600.

  • And it gives me 77.7 repeating indefinitely.

  • And it looks like I had two significant digits

  • in each of these original things.

  • I had 1.0 over here, not 100% clear

  • how many significant digits over here.

  • Was the spec rounded to the nearest 10 kilometers?

  • Or is it exactly 280 kilometers per hour?

  • Just to be safe I'll assume that it's

  • rounded to the nearest 10 kilometers.

  • So we only have two significant digits here.

  • So we should only have two significant digits

  • in our answer.

  • So we're going to round this to 78 meters per second.

  • So this is going to be 78 meters per second,

  • which is pretty fast.

  • For this thing to take off every second that goes by it

  • has to travel 78 meters, roughly 3/4

  • of the length of a football field in every second.

  • But that's not what we're trying to answer.

  • We're trying to say how long will take off last?

  • Well we could just do this in our head if you think about it.

  • The acceleration is 1 meter per second, per second.

  • Which tells us after every second

  • it's going 1 meter per second faster.

  • So if you start at a velocity of 0 and then after 1 second

  • it'll be going 1 meter per second.

  • After 2 seconds it will be going 2 meters per second.

  • After 3 seconds it'll be going 3 meters per second.

  • So how long will it take to get to 78 meters per second?

  • Well, it will take 78 seconds, or roughly a minute

  • and 18 seconds.

  • And just to verify this with our definition of our acceleration,

  • so to speak, just remember acceleration,

  • which is a vector quantity, and all the directions

  • we're talking about now are in the direction

  • of this direction of the runway.

  • The acceleration is equal to change in velocity

  • over change in time.

  • And we're trying to solve for how much time does it take,

  • or the change in time.

  • So let's do that.

  • So let's multiply both sides by change in time.

  • You get change in time times acceleration

  • is equal to change in velocity.

  • And to solve for change in time, divide both sides

  • by the acceleration.

  • So divide both sides by the acceleration you get

  • a change in time.

  • I could go down here, but I just want

  • to use all this real estate I have over here.

  • I have change in time is equal to change

  • in velocity divided by acceleration.

  • And in this situation, what is our change in velocity?

  • Well, we're starting off with the velocity,

  • or we're assuming we're starting off

  • with a velocity of 0 meters per second.

  • And we're getting up to 78 meters per second.

  • So our change in velocity is the 78 meters per second.

  • So this is equal, in our situation,

  • 78 meters per second is our change in velocity.

  • I'm taking the final velocity, 78 meters per second,

  • and subtract from that the initial velocity,

  • which is 0 meters per second.

  • And you just get this.

  • Divided by the acceleration, divided

  • by 1 meter per second per second,

  • or 1 meter per second squared.

  • So the numbers part are pretty easy.

  • You have 78 divided by 1, which is just 78.

  • And then the units you have meters per second.

  • And then if you divide by meters per second squared,

  • that's the same thing as multiplying

  • by seconds squared per meter.

  • Right?

  • Dividing by something the same thing

  • as multiplying by its reciprocal.

  • And you can do the same thing with units.

  • And then we see the meters cancel out.

  • And then seconds squared divided by seconds,

  • you're just left with seconds.

  • So once again, we get 78 seconds,

  • a little over a minute for this thing to take off.

This right here is a picture of an Airbus A380 aircraft.

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空中客車A380起飛時間|一維運動|物理學|可汗學院。 (Airbus A380 take-off time | One-dimensional motion | Physics | Khan Academy)

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    王怡婷 發佈於 2021 年 01 月 14 日
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