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  • "Today is going to be another, sort of, special topic. It's actually really important [inaudible].

  • One of my favorite things because it is so useful. We're going to be talking about using

  • nuclear overhauser effect in structured stereochemistry determination, and I'll try to show you why

  • I think this is so useful with some examples, maybe related things to the exam.

  • So in terms of what the nuclear overhauser effect is; I've been talking about this in

  • C13 NMR but not why this is useful. So the nuclear overhauser effect, or NOE,

  • is a change in intensity of the resonance of a proton or another nucleus, I'll put this

  • in terms of protons but I'm really talking about any type of nucleus, in response to

  • or upon irradiation of a nearby proton. And, so what do I mean; so let's say from

  • the point of view of a molecule I mean that you have two protons, of course it could be

  • a proton and a C13 in a molecule like so, where they're near to each other in space,

  • not necessarily in connectivity, that are just a few angstrom apart in space.

  • And, we're going to do something that specifically irradiates one proton and obviously what you

  • are doing is not a spatial resolution but rather frequency resolution; in other words

  • each protons appears at a different frequency and so you're going to hit one of these specifically

  • at this frequency and what that does here is it responds -- now, when you're irradiating

  • what you're doing is equalizing the population of alpha and beta states. And, when you do

  • that, that in turn alters the equilibrium population of alpha and beta states of other

  • nuclei that are nearby. And the way it does this is it opens new relaxation pathways.

  • And since it is a relaxation process, it doesn't occur instantly. It takes time on the order

  • of relaxation time; in other words, hundreds of milliseconds, typically, to build up.

  • And so, what you see, well, you see in your C NMR -- there are two reasons in the C NMR

  • that your C-H peaks, and C-H2 peaks, are bigger than your [inaudible]: one of these reasons

  • is the nuclear overhauser effect, carbon that has hydrogens attached to it is nearby to

  • a hydrogen, so when you irradiate the hydrogens you actually affect the population of alpha

  • and beta states in the carbon; another reason is that relaxation, because your pulsing reasonably

  • fast and [inaudible] usually relax slowly you end up with lower intensity but one of

  • the reasons is the NOE. Ok, so what does that mean for that hypothetical

  • cartoon of a molecule where you have Ha and Hb that are next to each other in space? It

  • means that if you have a spectrum that looks like this where you have Ha and Hb, if I irradiate

  • Ha, now the spectrum changes and we don't see Ha anymore and the peak for Hb gets a

  • little bit bigger. Now, these effects are pretty small in proton

  • NMR. The theoretical maximum H-H NOE is only 50%. And normally you see values that are

  • a lot smaller than that, you might see typically 10%. So what I've drawn here is a cartoon

  • where Hb is appreciably bigger, is actually not recall the case, its just going to be

  • just a teeny tiny bit bigger. Now, I said there's this effect that affects

  • carbon and because of the difference in magnetogyric ratio with proton and carbon you actually

  • have a bigger effect. So with H1 to C13 NOE here the affect is actually

  • 200%. So there you can have a peak get substantially bigger.

  • Now, NOEs involve relaxation, this in turn involves motion of molecules so like tumbling

  • motion which means the NOW is sensitive to the size of the molecule and how fast it tumbles

  • because that is going to affect different types of relaxation in molecules. So high

  • molecular weight molecules, so we're talking typically over 2000, but these numbers aren't

  • carved in stone, but let's say greater than 2000 or if you slow down the tumbling by a

  • viscous solvent, then your NOE is actually negative and the theoretical maximum is -100%

  • for H-H NOE. And this is important in protein structure

  • determination rather than in small molecule chemistry, which is where we focus. Now these

  • days, if you look at some of the natural products tat are getting published in the Journal of

  • Organic Chemistry or Journal of natural Products or JACS, some of these small molecules are

  • pretty hair molecules; in other words, hey are small molecules but they are big small

  • molecules. And that big small molecule regime is actually a pain in the neck, because what

  • happens as you go from small molecules that have positive NOE to big molecules that have

  • a negative NOE is what?" "No NOE?"

  • "No NOE. So the medium-sized molecules often end up have 0 NOE. And I really don't want

  • to be putting hard numbers on this because it depends on what solvent you're using, it

  • depends on the field strength of the spectrometer, it depends on the shape of the molecule, it

  • depends on the temperature, but I'm going to step out on a limb here and say molecular

  • weight range of say 1000-1500, which is a big small molecule, is often 0 NOE. Or close

  • to 0. And there is a related technique called a

  • rotating overhauser effect that's often used to bring out those NOE in that intermediate

  • range. Alright, I want to show you an example of a traditional NOE experiment; and I'll

  • show you an old example and then I'll show you an example that is sort of relevant to

  • organic chemistry research. I just want to show you the general gist of it; it's on the

  • first page on the handout. Alright, so this is an example in the book by Derome which

  • is a nice, a nice book, it's actually a precursor to Claridge, which is a book I've given you

  • some readings from that's sort of a second edition because Derome had passed away. So

  • here's a molecule, the particular molecule isn't important, buy you'll see the issues.

  • So this is an H1 NMR spectrum of the molecule and this is an NMR spectrum in which we've

  • irradiated one of the protons; specifically we irradiated this proton. And, in doing this,

  • the authors didn't quite equalize the population -- you still see a little bit of the peak.

  • The peak has gone from this over to the smaller version. And it's hard to tell if anything

  • has gotten bigger, it looks like that one has gotten bigger. But the way in which one

  • historically does this, because the spectrum involves such small changes, the way one historically

  • does this is called a difference NOE spectrum. And, difference NOE spectrum, one is literally

  • subtracting one spectrum from another spectrum; you're subtracting the unradiated spectrum

  • from irradiated spectrum so I'll put a minus sign, or actually I guess your technically

  • subtracting the [inaudible] and going ahead and coordinate transforming. And so I want

  • to point out the features that we see: so the fist thing we see of course is the now

  • irradiated peak is negative; after all, if we had something where we've almost equalized

  • the population or alpha and beta states and we take away something where we have a positive

  • peak you get a negative peak, but I want to show you the features.

  • Ok, the thing that's glaring you in the face in this literally textbook example is that

  • we see a nice NOE over to the peak here. So there's some spatial proximity between this

  • proton and this proton in the molecule. I want to show you some of the other features

  • in the spectrum: now, one of the things about the traditional NOE experiment is the conditions

  • of doing the irradiation, create little perturbations in the spectrum, and actually to do it right

  • what you do is you do one spectrum where you irradiate here in this case about 1.15 ppm

  • and this one in order to minimize the subtraction artifacts you actually go ahead and irradiate

  • somewhere else where nothing is, like over here or over here; but, even with that, there

  • are some perturbations. So this is what you would call a subtraction artifact. In other

  • words, it's not an NOE, we don't have a particular peak up or down, what's happened is there's

  • been an infinitesimally, a teeny tiny shift in the position of this peak because o f the

  • irradiation which gives us the positive character on one side and the negative character on

  • the other side. If I were looking at this I'd know just from recognition that there's

  • no NOE, but another way, a very good way, and something you really should do, is slap

  • an integral on it; and if you slap an integral on it of course the integral would go up as

  • the area registered and then go back down, and you'd end up, this would be an integral

  • here, so you'd end up with no net rise, no net area.

  • Now, one of the challenges, in any sort of conventional one-dimension NOE experiment

  • is selectively hitting this peak here. 'Cause you're trying to hit all of the lines here

  • in this peak, without hitting this peak; when the peaks are maybe 1/10 of a ppm apart, it's

  • hard to do that. It's easier if you have singlets; I usually tend to go to singlets if I can,

  • harder if you have multiplets because you have to apply a band of radiation that's wide

  • enough to hit this, without hitting this. And as you can see, we've got incomplete selectivity

  • here. So, to put it another way if I was testing a hypothesis that this proton is spatially

  • close to this one, and I hit this one and I see this one get bigger, but I also hit

  • this one a teeny tiny bit, there's this worry in the back of my mind: Oh maybe my hypothesis

  • wasn't being tested completely, because maybe I'm hitting this one as well, and maybe it's

  • this one enhancing this one. So what kind of experiment could you do to corroborate

  • this result; what kind of NOE experiment could you do to corroborate the result from this

  • experiment?" "Could you try to hit the number 1 peak?"

  • "Beautiful! Exactly! And, so we would try a corroboratory experiment as well

  • where you irradiate here. And usually NOE experiments usually end up being done in sets.

  • So you're going to do some 1-D NOE experiments on [inaudible], and this was part of the course

  • that everyone hated so I've cut it down; I've had you go ahead and hit every peak that could

  • be hit selectively in [inaudible]. It honestly doesn't take that long, imagine if this were

  • your thesis molecule it would be no big deal to spend three or four hours on the NMR spectrometer

  • for an important problem; but, we're 22 people here, you've got other things to do. So I've

  • cut it down to 1 or 2 nice, 1-D experiments where I basically preselected the key experiment

  • and we'll also do a [inaudible] experiment. But the 1-D NOE experiment is a beautiful

  • experiment because you can probe very specific questions.

  • So this is kind of a textbook example: I want to talk -- I'll give you a real example in

  • just a second and show you something I think is cool, if I can find my eraser that I've

  • seem to have misplaced here, but fortunately I have the emergency backup eraser -- anyway,

  • before I give you a real example and we look a [inaudible] spectra, I just want to show

  • you one other point of this that actually ties in sort of to thinking about problems

  • that you might encounter. So I just want to point out one sort f thing here, and that's

  • a three-spin system. So, sometimes observing an NOE doesn't necessarily mean proximity

  • and I'll show you an example. So a three-spin system wit h coupling, and again I'll give

  • you my little [inaudible] cartoon for things. So imagine that Hc is J-coupled with Hb, but

  • it's not spatially close to Ha, whereas Ha and Hb are close to each other. What can happen

  • is if I irradiate Ha, of course we'll see a NOE to Hb, in this case a positive NOE.

  • And remember, this is occurring because by leveling the populations of alpha and beta

  • states of Ha, I'm setting up new relaxation pathways that are perturbing the alpha and

  • beta states of Hb. But that perturbation then ends up altering the populations Hc, and in

  • this particular alignment, we end up with an NOE over here, a negative NOE. So, it's

  • usually going to be smaller, you usually can tell, but let me give you a real example;

  • and I think this was taken from the Derome book. So the molecule in this particular case

  • was a trichloro-toluene derivative, like so, and in this particular real experiment we

  • have an ortho proton and we have a meta proton. In this particular experiment they irradiated

  • the chloromethyl group over here and observed a 19.2% NOE over here to the ortho proton

  • and a -2.6% NOE over here to the meta proton. Now, I guess, looking at this particular molecule

  • it reminds me of your exam problem [inaudible], so on the first part of your midterm exam

  • remember the nitro-toluene problem and you were there just using a combination of understanding

  • coupling patterns and the inductive effect of a nitro group, the electron-withdrawing

  • effect, the resonance effect of the nitro group and the effect of a methoxy group, most

  • of you were able to assign your resonances and figure out among the 2,4-disubstituted

  • isomers and the 2,5-disubstituted isomers. Here, of course, the effects with chlorine

  • aren't as pronounce, just imagine in our minds eye that you had a molecule and you were trying

  • to tell whether it was the 2,4 or the 2,5 compound, and of course maybe in this particular

  • case, you wouldn't have as clear a differentiation in chemical shift, but if you look at this

  • here you can imagine, if we irradiated in this case you would see an enhancement in

  • this ortho proton here which would be a doublet with only meta coupling, a tight doublet;

  • if you irradiated over here in this molecule, you would see the ortho proton enhanced which

  • would be a doublet with ortho coupling. So in other words, even if the spectra of these

  • two molecules, the 2,4 and 2,5 isomers, were very similar in chemical shift, you would

  • be able to tell, from an NOE experiment, which isomer you had by telling whether it was a

  • doublet of 8 Hz being enhanced or a doublet of 3 Hz being enhanced. So that's an example

  • immediately that I can hand you of the utility of an NOE experiment. Now, another example

  • that I can give you, and again I'll harken back to the exam to a problem that I guess

  • about 2/3 of you did, and that was the beta-lactone problem and there we weren't trying to tell

  • stereoisomers apart, but imagine for a moment, I'll get [inaudible] the beta-lactone case

  • as an example. Imagine for a moment we have a beta-lactone and imagine instead of just

  • having a methyl group at this position, imagine that we had methyl group and an ethyl group

  • at these two positions, and now we had a methyl group over here of unknown stereochemistry.

  • You can now imagine that you irradiate this methyl group, this is going to be your methyl

  • doublet [inaudible], and now you ask is it enhancing the CH2 group of the ethyl group

  • or is it enhancing the CH3 singlet of the methyl group and you can again address the

  • question of whether your diastereomer the cis or the trans relationship between the

  • two methyl groups; in other words, whether we had this diastereomer or this diastereomer."

  • "And, it would enhance the one that is one the same side as the [inaudible]?"

  • "Well, it would enhance it more, and you're asking a very, very good question. So, the

  • question that you're asking is basically: Is the NOE a litmus test? And the answer is

  • no; this is why comparison is so important. And now I didn't happen to include these in

  • the handout for the class but I have a very similar example, and I'm going to show you

  • exactly what it means and then we are going to talk about some distances. And actually,

  • you know I've been harping on the value of molecular models, molecular models become

  • really, really, really useful when you want to ask questions about distances.

  • Alright, so let's take a look at a real example, this is just one that I pulled from my own

  • experience with the use of NOEs to determine stereochemistry. The example that I'm going

  • to [inaudible] is actually a cool reaction, it's a named reaction that probably nobody

  • in this room has heard of, it's the McCoy reaction and if the professor Van Vranken

  • asks you for a mechanism for it I bet you would all get it. So, the substrate for the

  • reaction is an alpha-halo carbonyl compound. This happened to be a silo ketone or what's

  • called an acylsilane and it's a TBDMS [inaudible] but you can also do this for an ester. And

  • when you take this compound, an alpha-halo carbonyl compound and you treat it with LDA

  • and then you treat it with and alpha-beta unsaturated carbonyl compound, in this case

  • I used [inaudible], you get a cyclopropane product, and I'll draw that for you. And the

  • great thing about reactions invented early on in the century is that every new reaction

  • that you invent can get you a name [inaudible], so this is the McCoy reaction. Alright, so

  • the product that we get is a cyclopropane of undetermined stereochemistry, and unfortunately

  • in this particular example we have a 3:1 mixture of diastereomers. Alright, let me pull down

  • the screen and give us a chance to take a look at the spectrum of these two diastereomers.

  • Alright, so we have these two diastereomers and we'll call them isomer B and isomer A.

  • And, just to get our bearings straight the region around 7ppm is the aromatic region

  • in each of these. The region over here is the methyl groups on our silicon. Here is

  • our tert-butyl on the silicone. Here is our isolated methyl group, and these are the ring

  • protons on the cyclopropane ring. And so on isomer B we see a similar thing, we see our

  • aromatic resonances, we see our ring CHs, we see our methyl, our tert-butyl, and now

  • we see our two methyls on silicon. Alright, why do we get two peaks for two methyls on

  • silicon?" [Inaudible]

  • "Diastereo-what?" [Inaudible]

  • "They are diastereotopic! Now, remember I said when you have any sort of stereocenter

  • in a molecule and now you have a methylene group with two hydrogens on it or a carbon

  • with two methyls on it, those are diastereotopic. They're topologically different from each

  • other. In one case, they show up at pretty similar chemical shifts; in other case, which

  • is interesting, they have a high degree of what we call magnetic [inaudible], in other

  • words difference in chemical shifts. Now this is an example of where the NOE just shines

  • as an experiment because we have a testable hypothesis built into the molecule. In the

  • diastereomer on the left, the methyl group is going to be relatively close to those hydrogens

  • on the ring; in the diastereomer on the right, the methyl group is relatively far away, and

  • we're fortunate enough to have both of them. So, let's start with our NOE experiment on

  • isomer B. So in this particular NOE experiment, we irradiate that methyl group and this is

  • the difference NOE so this is the spectrum of isomer B, and this is the difference NOE.

  • And we don't see a heck of a lot, you can see this is an example of a subtraction artifact

  • here, but you look and you see very, very clearly those two ring protons have nice NOEs.

  • I want to know how big an NOE: I can slap my ruler on this integral, I've already done

  • this, this distance here was 74 millimeters, and that's for 3 hydrogens. And over here

  • I slap my ruler on this integral and it comes out to 2.1 millimeters for one hydrogen and

  • over her e I slap my ruler on it, it's 2.5 millimeters for one hydrogen. And so if I

  • take 2.1 divided by 74 divided by 3 I find out its equal to 0.085 or I have an 8.5% NOE

  • and if I do the same over here I find if I have the value 10% NOE, and so I'm very happy.

  • I irradiate, I get about an 8-10% NOE, and I say great! We know what a diastereomer means.

  • Now, you want to be careful; you do this same experiment, and I was fortunate we had both

  • diastereomers, you do this same experiment here, so this is diastereomer A, and we irradiate,

  • and we see a teeny tiny enhancement, it's little. A little baby NOE. Over here, and

  • over here it's about 0.5 millimeters each, and this one on this particular example was

  • about 73 millimeters for each hydrogen, and it ends up to about 2% NOE. And it's nice

  • with both diastereomers in hand, we've done a comparison. You irradiate one diastereomer's

  • methyl group, you get a nice NOE, the other you get a little NOE. The first one is cis,

  • A is cis, and B is trans. But, imagine, imagine for a moment, that I've

  • gotten this reaction in the diastereomer [inaudible], and I've only gotten one diastereomer, and

  • imagine I really, really wanted it, in order to make a natural product, to be the cis diastereomer

  • and I do it and I say 'Oh yeah, look I got an NOE!' Imagine the trouble [inaudible],

  • because then I would go on with this and think 'Oh, I have what I want,' and later on I make

  • my natural product, if I were making a natural product, and I find it doesn't match the published

  • spectrum, and my thesis would be titled 'Total Synthesis [inaudible],' whatever the natural

  • product is. [Inaudible]. I would still get a Ph.D. but I wouldn't get a paper in JACS

  • or something [inaudible]. So you really need to be careful, this was a good example. Now,

  • if you look in here, there are some teeny tiny hints; so imagine this was the only one

  • I had, there are some teeny tiny hints that this really is the trans one. And if you look

  • at the integrals, and I like to slap an integral on everything. Why do I like to slap an integral

  • on everything? 'Cause it's easy to see. If you have a big peak, if you have a double

  • that's standing up there nice and tall, it's easy to see it get bigger. But imagine you

  • had a little peak that's split into a big multiplet that's short, and it gets just a

  • little bit bigger, you may not see it. So you slap an NOE everywhere, and you say 'Oh,

  • wait a second, ok I've got some subtraction artifacts here but I see a teeny tiny NOE

  • here. You can see this guy here has just gotten a teeny tiny bit bigger, I wouldn't stake

  • my dissertation on it, but if you measure that integral it's about 1.0 millimeter, that

  • translates to about a 4% NOE, right, because it's 1.0 divided by 73 divided by 3 is equal

  • to 0.04, 4%. So I look at that, and I say 'Oh wait a second.' So, in other words, if

  • I only have this diastereomer, I wouldn't want to assign it on the basis of that NOE,

  • because we are seeing a little NOE between the cis phenyl group and the methyl group

  • and a little NOE with those trans hydrogens and the methyl group but I'd at least be able

  • to look at this spectrum and say, 'Wow,' pull myself back, even though I wanted the isomer

  • in which the methyl group was cis to the hydrogens there was enough data saying it isn't. In

  • fact, there is a good deal of data saying it's trans to those hydrogens. So, anyway,

  • be careful with NOEs, usually we're talking about having multiple data sets, multiple

  • NOEs pointing in a particular direction. Now, this cis-trans business really brings up a

  • very, very important question, and that question is what is close, and what is not close? How

  • close is close? Alright, let's talk a little bit about molecular

  • geometry first, talk about [inaudible]. The Van der Waals radius of hydrogen, anyone know

  • it off the top of their head?" [Inaudible]

  • "A few good numbers to keep in your head." [Inaudible]

  • "Ok, let's take a carbon-carbon bond, what's a carbon-carbon single bond?"

  • [Inaudible] "One picometers, or... I'm kind of an angstrom

  • kind of guy. 1.54 angstroms. So the Van der Waals radius is on that same scale, it's 1.1

  • angstroms. The C-C bonds, the C sp3 sp3 single bond is 1.54 angstroms. Ok, so that's at least

  • kind of calibrated us. So, what does that mean? That means that if 1.1 angstroms is

  • the radius, 2.2 angstroms for two hydrogens is going to be touching; so 2.2 angstroms

  • is close, so that's at least a calibration. Ok, so another thing that's important is how

  • NOEs vary. NOEs scale as distance to the inverse 6. I always calibrate myself in my mind by

  • setting up a little table. When we were talking last time about dynamic effects in NMR and

  • I said, 'Alright, what's 10 kilocalories per mole?' Well 10 kilocalories per mole becomes

  • slow at negative 50 degrees C. 15, kind of at room temperature, is right about the cross

  • over; 20 or a hair less than 20 is sort of crossing over [inaudible]. And we can do similar

  • things here, so let me calibrate myself. So let's take 2.5 angstroms, if I take 1 over

  • 2.5 to the 6, that's equal to 4.1 times 10 to the negative 3. So let's say 2.5 angstroms,

  • we'll call that close. And if we say the relative NOE, for that, let's call that one. And then

  • I'm just going to calibrate myself from there. So let me take 3.0 angstroms for comparison

  • and if I now take 1 over 3.0 to the 6, I get 1.4 times 10 to the negative 3, and so the

  • relative value is 0.33. And if I do the same for 3.5 angstroms, take 1 over 3.5 to the

  • 6, that gives me 5.4 times 10 to the negative 4. The relative value is 0.13. Ok, what does

  • that mean? That means, if you imagine 2.5 angstroms and say that's close, that gives

  • you an NOE of a certain intensity, let's say that intensity was 10%, like we saw in our

  • cyclopropane. Now imagine we have a distance of 3.0 or 3.5 angstroms, well, I expect to

  • still see some NOE, but that NOE would be weaker, it would be like 3.3% or 1.3%. This

  • is exactly what we are seeing in the cyclopropane case. The cis isomer gave us an NOE that was

  • about 10%. The trans isomer gave us an NOE that was sort of, you know, 2.0%, somewhere

  • around there. It was detectable but obviously not as strong. the trans isomer gave us an

  • NOE that was sort of, you know, 2.0%, somewhere around there. It was detectable but obviously

  • not as strong. Let's call this medium. Let's just continue

  • our calibration. 4.4 angstroms, 1 over 4 to the 6, is equal to 2.4 times 10 to the negative

  • 4. And now we're at 0.06. Now you might say, well, by the time you're at 4 angstroms, let's

  • call it 'not so close.' What do I mean? I mean, you might still get a teeny tiny NOE

  • at 4 angstroms but it's not going to be a really big NOE, but again, I wouldn't stake

  • a stereochemical determination on seeing that; if I see an NOE between two protons, I say

  • 'Oh they can't be cis, they can't be close, because I see an NOE is very small.' You might

  • say, 'Wait a second, he just said in class that you could still see something at 3 and

  • a half or 4 angstroms.' Now I'm going to calibrate us with models in a second which is one of

  • the reasons as I said earlier, I've been making such a big deal about models. I'll give you

  • one other number: 1.8 angstroms. 1.8 angstroms is the distance between two hydrogens on a

  • methylene group; those two hydrogens are jammed in each other and closer than Van der Waals

  • radius. If I take that, the relative would be 7.2. So what does that mean? That means

  • if I have two diastereotopic hydrogens in a methylene, and I irradiate one, you may

  • well see a very, very, very strong NOE. That's like the beta-lactone, when you had the two

  • diastereotopic hydrogens. If I irradiated one, I could well see a strong NOE. Ok, what's

  • close ,what's far. I made up these models; I didn't have [inaudible]

  • at the time, I don't think it had even been invented [inaudible]. Same basic thing [inaudible].

  • Ok, so I just took a few systems that I use to calibrate my own thinking. We just saw

  • an example of a cylcopropane with a methyl group on it, and guess what? The hydrogen

  • on the cyclopropane is pretty darn close to a hydrogen, the methyl group on the cylcopropane

  • is pretty darn close to a cis hydrogen, 2.4 angstroms, 2.2 angstroms in this particular

  • model. But at the same time, we see 3.5 angstroms for the trans hydrogen, which is the exactly

  • the sort of thing we saw on our NOE experiment. Alkenes, alkene stereochemistry, this is great.

  • you have a methyl group on an alkene and you want to know which hydrogen is cis to it,

  • which is trans; the cis hydrogen is 2.3 angstroms, clearly close, but the trans isn't infinitely

  • far away, it's 3.7 angstroms. I did the same with the cyclobutane, cyclopentanes can be

  • very tricky. You know, NOEs really aren't a litmus test with cyclopentanes; I put a

  • methyl group on a cyclopentane, and you'll look at the methyl group, and yeah it's close

  • to the cis hydrogen, it's also close to the trans hydrogen. You're going to be getting

  • some 5 membered ring compounds and you're going to have to look at multiple NOEs to

  • see which is close which is far. I will also point out, and you can't see it on this model

  • but it'll come up later, when you have a cyclopentane and you have two hydrogens in a 1 and 3 positions,

  • if you see a NOE between them that really can only be cis. You won't be guaranteed to

  • see it, it'll depend on the pucker of the ring, but you will see it if it's cis. Or

  • if you see it, it pretty much must be cis. I put an axial methyl on a cyclohexane and

  • you can see that axial methyl bangs into the hydrogens here very nicely. This is a methoxybenzene

  • and you can see the ortho relationship as well, so. Alright, I want to finish up with

  • a couple of additional comments and one last example. So the experiment that is now run

  • is a PFG-NOE, also called a gNOE, so this is a more modern version of a difference NOE

  • experiment. It's a NOE experiment that uses pulsed-field gradients. And I can talk more

  • about that later but right now I'll say it's cleaner than the difference NOE. You'll be

  • doing this with your [inaudible]. Another experiment is a NOESY, we'll be talking about

  • it later, but it's a 2-D NOE experiment. We'll be using it later on. I'll give you one example.

  • Very data rich. And there are NOEs and again we'll be talking more about this later on.

  • ROESY experiment which is NOE in a rotating frame and that's particularly good for intermediate

  • sized molecules. Which give near 0 NOEs. Alright, I want to conclude with one class example.

  • And I'll just show you an example of how beautiful a set of NOEs can be from a NOESY experiment

  • where you get multiple data that give you confirmation in stereochemistry. So this is

  • a molecule, a natural product, it's a [inaudible] natural product called Aphanamol. And this

  • is a NOESY experiment of it. NOESY experiments are 2-D, they give cross peaks, based on spatial

  • proximity, so they are NOE cross peaks. And if you look at this, of course, what's cool

  • is we have this 5 membered ring fused to a 7 membered ring. I'll draw it out flat just

  • so you can see it. And of course you have, you have an alkene here, and of course you

  • have some stereochemical issues because you have a ring junction in the molecule, and

  • I'll tell you now that the ring juncture is cis, but of course you'll want to be able

  • to tell that, because you wouldn't necessarily know that. And there's an isopropyl group,

  • and the isopropyl group is cis to the hydrogens of the ring junction. So now let's take a

  • look at the NOEs we see and how they help show the stereochemistry. So, for example,

  • we see a nice NOE between the hydrogen at 4 and the hydrogen at 11, they are cis to

  • each other, they give rise a strong NOE. Now, you get many more corroboratory NOEs. So the

  • hydrogen at the 3 position, for example, is cis to the alkene group and they [inaudible]

  • an NOE and we see that NOE over here. So you're starting to get pieces of the molecule sewn

  • together on not only the stereochemistry but also the conformation of the molecule, the

  • shape of the molecule. Remember I told you I have a very simple minded view about medium

  • sized rings. I say always start with a cyclohexane and go ahead you can sort of think of a cyclohexane

  • and perturb it I mentioned early on you're going to get some seven membered rings and

  • you can think of it kind of like an extended cyclohexane. We see this here in the seven

  • membered ring. The seven membered ring puckers and so the hydrogen at the 1 1 position and

  • one of the hydrogens at the 8 position are basically like diaxial hydrogens to each other.

  • And we see that very nice NOE over here. Remember how I said you can see NOEs on alkenes, and

  • we see this NOE here between proton 5 and 15 on the alkene. So this is really a beautiful

  • data set because it gives us information on the conformation and stereochemistry of the

  • molecule and you can then imagine building a model looking at your distances, saying

  • does this making sense, looking at your dihedral angles, and saying ok, are we seeing coupling

  • behavior here and coupling constants that match this, is everything consistent with

  • this model? Could there be any other stereochemistry which could be consistent with the data? Could

  • there be any other conformation that could be consistent wit h the data? And that's one

  • of the reasons that modeling and NMR work so well together. Alright, that's what I'd

  • like to say for today. We'll talk about, I think, the [inaudible] experiment next time

  • and we get to add that to our repertoire."

"Today is going to be another, sort of, special topic. It's actually really important [inaudible].

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B1 中級

化學203.有機光譜學。第19講。核超豪斯效應 (Chem 203. Organic Spectroscopy. Lecture 19. The Nuclear Overhauser Effect)

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    Cheng-Hong Liu 發佈於 2021 年 01 月 14 日
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