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  • >> All right what I'd like to do today and on Monday is to talk

  • about NMR spectroscopy and kind of how NMR spectroscopy works.

  • I'll call it concepts in theory and for me what I want

  • to do is give my perspective on NMR

  • which is not a highly mathematical perspective.

  • In fact, everything I write up here today is going to really be

  • in terms of numbers is actually going to be simple arithmetic

  • and most of it is more an embodiment of the idea rather

  • than a specific calculation that you quote need to do.

  • So where NMR begins is with the concept that a nucleus

  • of certain sorts and I'll just write a proton for now,

  • has a spin to it and when you have a spinning charge it

  • generates a magnetic dipole.

  • And if you apply a magnetic field,

  • we'll call that magnetic field B naught,

  • then you have two different spin states or more

  • and you'll see examples of this in the case

  • of nuclear quadrupoles but let's start with the case

  • of a proton or a C 13.

  • You have two spin states that can exist, quanti-spin states.

  • The spin of the nucleus can either be spin up,

  • so if it's spin up, in other words in the same direction

  • as the applied magnetic field then this is going to be lower

  • in energy so I'll put, by up I mean aligned with B naught

  • and if it's spin down meaning aligned

  • against B naught then we're higher in energy and we'll refer

  • to throughout our discussion.

  • We'll refer to the lower energy state as the alpha state

  • and to the higher energy state as the beta state.

  • Now different types of nuclei have different spin properties.

  • Rather than trying to start with generalizations

  • about rules I'll come to those in a moment

  • because at some point you'll be wondering

  • in your project well could I study chlorine 35 or something

  • like that, let's just start with typical nuclei studied.

  • So if you go for example, to the 400 megahertz NMR spectrometer

  • in my building in Natural Sciences 1,

  • you'll find that that instrument can study protons.

  • I'm going to write a couple of numbers for these.

  • I'm going to write the atomic number and the mass number.

  • And it can study C 13 and it can study F 19

  • and it can study P 31.

  • And these are common nuclei that are often studied by NMR.

  • They're easy to study.

  • What do these nuclei have in common?

  • They have a one-half indeed and what,

  • forgetting their spin state what property

  • on the blackboard do they have in common?

  • >> Odd numbers of protons and neutrons.

  • Odd numbers of protons and neutrons

  • or more specifically we can group them

  • that their mass number is odd, specifically that the sum

  • of their protons and neutrons is odd.

  • So nuclei with an odd mass number have a nuclear spin

  • and the quantum characterization

  • of nuclear spin is what's called a spin number

  • and we'll call the spin number i. It really doesn't matter what

  • we call it but they call it i and so that number is going

  • to be one-half and that gives you all the ones up here

  • but if we want a generalize more nuclei

  • with an odd mass number will have a spin number of one-half

  • or three-halves or five-halves, etcetera.

  • So that's the more general idea.

  • The ones with one-half are easy

  • because they have what's called the nuclear dipole.

  • If you have three-halves or five-halves or one as we'll see

  • in just a moment you have what's called a nuclear quadrupole

  • and then those tend to be harder.

  • So all the ones here of i equals one-half have spin states

  • so we have the quantum number

  • and then the two spin states they can have

  • and so the spin states are plus or minus one-half.

  • So that's all of these H 1, C 13, oops, F 19 we'll come

  • to nitrogen in just a second and P 31.

  • Now a nucleus with a spin number

  • of three-halves can have spin states of plus or minus one-half

  • or plus or minus three-halves

  • and this is what you call a nuclear quadrupole.

  • Most of the time, many of the times nuclei

  • with nuclear quadrupoles don't behave as if they're NMR active.

  • In our next lecture we'll get to the concept of relaxation.

  • Relaxation basically is how quickly you flip

  • between the two spin states or in this case,

  • between the four spin states or three in some cases

  • and often they flip very quickly

  • which means you can't study them by NMR.

  • Relaxation is affected by properties like symmetry as well

  • and I'll get to that in a moment with another example.

  • But if I give I an example of a nucleus with a spin state

  • of three halves, of boron there are two different isotopes.

  • There are B 10 and B 11 and B 11 has, I think they both do

  • but B 11 has a spin state of three-halves and if you look

  • at the NMR spectrum of borohydride

  • from this one what you see

  • in the H1 NMR is you see four lines equally spaced

  • and of equal height due to the hydrogens coupling

  • with the nuclear quadrupole and it's very unusual

  • because normally we think about splitting into a doublet

  • or if you're thinking a triplet or a one to two to one triplet

  • or quartet or one to three to three to one triplet,

  • but what's happening here is the hydrogen C boron

  • and they see either the boron having a spin state

  • of negative three-halves or negative one-half

  • or positive one-half or positive three-halves

  • and so you see the four spin states

  • and that gives are rise to four lines.

  • All right but so let's look at some other nuclei

  • with an odd mass number.

  • [ Silence ]

  • So one very important nucleus in biomolecular NMR is N 15.

  • Nitrogen 15 has a spin number of i equals one

  • and indeed N 15 is often studied.

  • Most nitrogens, not N 15.

  • We talked about this when we talked

  • about mass spectrometry we said that the natural abundance

  • of N 15 is 0.38 percent and that's really, really low.

  • The isotopic abundance of C 13 spin active is one-and a half

  • percent is 1.1 percent and you know

  • that carbon NMR is not very sensitive.

  • You need to have a reasonable sample size, more than you have

  • for protein typically

  • and sometimes often collect data for much longer.

  • Well by the time you're down to .38 percent studying it

  • at natural abundance is pretty hard so often you do this

  • with isotopic labeling.

  • Two dimensional N 15 based techniques are a mainstay

  • of protein NMR spectroscopy and in general

  • since most proteins are expressed these days what you do

  • is you simply grow up your e-coli

  • with N 15 ammonium chloride and they absorb that and use it

  • to make up the amino acids

  • and then you can get a fully N 15 labeled protein

  • which is very useful.

  • N 15 is starting to become more important

  • in some natural product structure determination.

  • Alkaloids as you may have seen for example

  • in Neil Gard's [assumed spelling] talks have lots

  • of nitrogens in them and so being able to figure

  • out the positions of those nitrogens can be very important.

  • In the case of something like an alkaloid

  • or a synthetic project you might not be able to put N 15 in

  • and NMR spectrometers are becoming more sensitive

  • and so it becomes not completely nuts to think

  • about using N 15 techniques in your NMR.

  • At the end of the course I may talk

  • about some two the dimensional techniques with N 15

  • at natural abundance that people are doing just

  • because I think it's useful but that won't be until the end

  • of November or December.

  • Another common, well not common, another nucleus is oxygen,

  • O 17 remember we said is only low natural abundance.

  • It's only very low I should say.

  • It's only.04 percent and oxygen 17 has a spin number

  • of i is equal to five-halves so that's a nucleus

  • that can have six spin states, negative five-halves,

  • negative three-halves, negative one-half, positive one-half,

  • three-halves, five-halves, etcetera and so it has sort

  • of doubly damned and so it's not generally studied.

  • All right so that takes care of our nuclei

  • with odd mass numbers.

  • Now the next class I'll talk about is

  • if you have an even mass number and an even atomic number

  • so that's easy those are nuclei like C 12,

  • O 16 and the answer is very simple.

  • Those have a spin number of i equal zero.

  • They have no spin and those are NMR inactive.

  • Since you don't have different spin states you can't have

  • quanti-transitions between spin states

  • so there's no way they can be studied by NMR spectroscopy.

  • So the last class then becomes nuclei with an even mass number

  • but not atomic number so that would include nuclei

  • like deuterium, nuclei like N 14.

  • I guess that would be the common ones we'd encounter

  • in organic compounds.

  • These all have a nuclear quadrupole.

  • Remember a quadrupole is anything

  • that doesn't have a dipole, i.e. just spin up, spin down,

  • i.e. i equally one-half so these all have a nuclear quadrupole

  • and a spin number i equals 1, 2, 3, etcetera so for example,

  • if you take deuterium you have a spin number i equals 1

  • and so you have three spin states available to it

  • and you know the direct manifestation of this that many

  • of you have seen with your own eyes?

  • Who's run a C 13 NMR, most of you?

  • What solvent did you use?

  • Chloroform, right, the first solvent most of us reach

  • for because it's pretty cheap as solvents go and pretty good

  • at dissolving organic chemicals.

  • It's cheap because it doesn't have

  • that much deuterium in it, right?

  • You only have one deuterium for all that weight of chlorine.

  • You need to deuterium to get the deuterium lock

  • for NMR spectroscopy and what do you always see

  • when you run an NMR spectrum in deuterochloroform?

  • >> A triplet?

  • >> A triplet and a very interesting sort of triplet

  • so for CDCl 3 in the C 13 NMR you see a one-to-one-to-one

  • triplet centered at 77 ppm.

  • >> These are really jammed together.

  • >> It's really jammed together.

  • The separation between the lines is 32 hertz,

  • in other words the distance

  • between these two lines is 32 hertz.

  • The distance between these two lines is 32 hertz.

  • If you're running your spectrum on a 500 megahertz spectrometer

  • that means the carbon NMR is running at a 125.7 megahertz.

  • I'll come back to that in a second

  • which means 1 ppm is 125 hertz

  • which means the lines here are separated by about three-tenth

  • of a ppm and that's on a big roughly 200 ppm scale

  • so as James said those lines are really close together

  • and the manifestation is it's a one-to-one-to-one triplet

  • because to a first order approximation a third

  • of your deuterons are in spin state negative one.

  • A third of your deuterons are in spin state zero and a third

  • of your deuterons are in a spin state of positive one

  • and we'll see in a moment that they're minuscule,

  • minuscule differences in the population of the spin states

  • and that's really, really important.

  • We'll also see in a moment that that number 32 comes back

  • when we see something else.

  • All right most of the time--

  • so deuterium is kind of special among nuclear quadrupoles

  • in that most of the time nuclear quadrupoles,

  • nuclei with quadrupoles undergo rapid relaxation

  • but deuterium is special.

  • It's relaxation is slow and I'll just say to put it

  • in simple terms is effectively like NMR inactive.

  • So many of the nuclei with nuclear quadrupoles

  • like chlorine 35 and chlorine 37 how do we know that those have,

  • all right I will take that back.

  • We can't know that they have a nuclear dipole

  • or a nuclear quadrupole but we know they have a spin number

  • of one-half or three-halves or five-halves or seven-halves.

  • They happen to have the higher ones so we never see J coupling.

  • We never see spin-spin coupling to chlorine 35 or chlorine 37,

  • if we did your carbon spectrum here,

  • your C 13 NMR spectrum would actually be much more

  • complicated because you'd be seeing splitting

  • from the chlorines.

  • Okay, so nitrogen 15, I'm sorry nitrogen 14 also has a

  • nuclear quadrupole.

  • It has a spin number of i equals 1

  • and so normally you have rapid relaxation, so for example,

  • if we come to that amide what we were dealing with before

  • when I asked you about the IR spectrum and if we look

  • at the NMR spectrum of this amide of course most

  • of your nitrogen, 99.62 percent

  • of your nitrogen virtually all is N 14 in here

  • and we don't see J coupling to this proton

  • so as I said the fact that we do see J coupling

  • between the deuterium,

  • J coupling just means spin-spin coupling to the C 13 is

  • because deuterium is the odd ball here

  • and that it often doesn't undergo relaxation

  • but most nuclei with a nuclear quadrupole don't show nuclear

  • coupling because we have rapid relaxation.

  • As I was saying earlier with my example

  • of borohydride symmetry is the odd ball on

  • or highly symmetric species end up being odd balls

  • in that you have slow relaxation

  • so borohydride B H 4 minus has tetrahedral symmetry

  • so you see coupling from the boron to the hydrogens a case

  • that you may see and I saw first by accident one of those cases

  • where you simply dissolve out the compound in a solution

  • and you get an NMR spectrum and so this is ammonium chloride

  • in DMSO, ammonium chloride has NH 4 plus Cl minus

  • and the ammonium has tetrahedral symmetry

  • and the first time I happen the accidentally have this

  • in a sample and took an NMR spectrum as I said in DMSO D6,

  • I saw an NMR spectrum with 3 peaks that were so far apart

  • that you barely could tell they went together except the odd

  • thing was they were all the same height

  • and this spacing was the same as that and it was what's going on?

  • Oh, wait that's your nitrogen so this is your J 1 NH.

  • In other words your one bond coupling between the nitrogen

  • and the hydrogen and I don't remember what the coupling

  • constant is but it's big.

  • >> It was always produced as J no matter?

  • >> J is, yeah J is the term that we use to refer

  • to spin-spin coupling.

  • >> That's not just from proton NMR, right?

  • >> That's not just proton NMR.

  • So we would describe this as J 1 CD equals 32 hertz.

  • And later on when we start to talk

  • about 2D techniques like HMQC and HMBC.

  • Terms like J 1 CH, J 2 CH and J 3 CH, in other words one bond,

  • two bond and three bond carbon hydrogen couplings will become

  • are very important in structure determination.

  • All right so when we last left our spinning nuclear dipole he

  • was spinning in the presence of an applied magnetic field

  • and I said there were two states, the alpha state

  • and the beta state and the alpha state was lower in energy

  • than the beta state so I can make a little diagram,

  • E and I can show just like you learned in electronic structure

  • where you learned for example, you have pi orbitals

  • and pi star orbitals and you have populated electrons

  • in your two orbital.

  • Here we can think about populations of nuclei.

  • It's a little bit different in a sense we're talking

  • over the entire sample but if we have our applied magnetic field

  • B naught and we have our alpha state and our beta state,

  • remember the alpha state is aligned with magnetic field,

  • we can think about some nuclei being in the alpha state

  • and some nuclei being in the beta state

  • and there's an energy gap between these two spin states

  • and we can think about the energy to flip a nucleus

  • from the alpha state to the beta state as the energy of a photon,

  • in other words an energy quantum in the electromagnetic spectrum

  • and that delta E is going to be H NU.

  • In other words the energy, the difference, the frequency

  • of a photon to flip a nucleus from the alpha state

  • to the beta state is going to be dictated by that difference

  • in energy such that E equals H NU, delta E equals H NU.

  • Now what sort of energies are we talking about?

  • Well we're talking about 500 megahertz for protons

  • so we're talking about radio frequency,

  • so let me just give you a calibration here.

  • So if you think about UV and our delta E so maybe if I think

  • about UV and I think about a chromophore, maybe I think

  • about my mercury line at 254 nanometers from my TLC lamp

  • and I think about a chromophore say containing a benzene ring

  • or a methoxybenzene ring and maybe I say all right,

  • if we just take 254 nanometers and I go ahead and plug

  • into you remember C equals lambda NU

  • so that's our wavelength and you calculate NU the frequency

  • and then you calculate E equals H NU and you plug

  • in the Planck's constant you get the detective to E corresponding

  • to a photon in the UV is 113 kilocalories per mole.

  • And then you stop and you think like an organic chemist

  • and you say okay, wait what's 113 kilocalories per mole?

  • What's the difference between a pi and a pi star?

  • It's a little stronger than the strength

  • of a carbon-carbon single bond, a little stronger

  • than the strength of a carbon hydrogen bond

  • in other words the energy difference

  • in the UV spectrum corresponds to the strength of bonds.

  • And now if you think about, so this is our UV,

  • if we think about UV, oh, I guess I wrote UV.

  • All right if we think about IR and I think

  • about a typical stretch,

  • well we've been talking a lot about carbonyls.

  • Carbonyls absorb at about 1700 wave numbers.

  • We said that wave numbers was centimeters per wave

  • which meant your wavelength is 117 hundredth of a centimeter

  • and that's lambda and then you calculate your frequency out

  • and it's in the infrared range and then you plug

  • in to equal delta equals H NU and you find

  • out that delta E is equal to 4.87 kilocalories per mole.

  • And you say okay that kind of makes sense.

  • I know that infrared is lower in energy than UV.

  • It's lower in energy than visible.

  • I know that we don't have sufficient energy

  • to break bonds in the IR.

  • Indeed all we're doing is kicking them

  • up a higher vibrational state

  • and you remember you're energy curves

  • with your vibrational states

  • and it takes many jumps before you get to the point

  • that you're dissociating bonds.

  • Well if we do the same for NMR

  • and let's say we take 500 megahertz and we plug in

  • and again plug in E equals H NU then delta E is equal to 0.0477

  • but it's not kilocalories per mole.

  • It's calories per mole.

  • So the first thing when you see NMR spectroscopy is you're

  • getting dinged badly because the technique involves very little

  • energy absorbent.

  • In other words when you're measuring a UV spectrum it's

  • very easy for a detector to detect the energy of a photon

  • and when you're measuring an IR spectrum it's very easy.

  • And already your detectors have to be much more sensitive

  • and it's going to get worse from there.

  • All right so we talked about delta equals H NU,

  • what's new for a-- that's not a pun,

  • if it were it would be terrible.

  • What's new for a nucleus?

  • NU is dictated by gamma B naught over 2 pi.

  • Okay, well so far so good.

  • I said B naught is the applied magnetic field so if you look

  • at this you'd say well this kind

  • of makes sense bigger applied magnetic field means bigger

  • difference in energy, right?

  • Delta equals H times gamma B naught over 2 pi

  • so that kind of makes sense.

  • All right let's just take a look at that.

  • What does that mean?

  • There's a linear proportionality,

  • so if I again plug into this equation I get that,

  • so in other words if I just go ahead and plug

  • into this equation I'll come back to gamma in a second.

  • We find out that if we apply 70, 500 gauss magnetic field

  • that leads to 300 megahertz for H 1.

  • If we go to a higher magnetic field that leads

  • to a higher frequency and it's going to be in a linear fashion

  • so if I apply 117, 500 gauss magnetic field now we're

  • at a 500 megahertz NMR spectrometer

  • and if you make a 300 megahertz NMR spectrometer you have an

  • electromagnet like this maybe this big,

  • super-conducting magnet this big where you have a coil of wire

  • with electricity passing through it, in liquid helium

  • in the wire is super-conducting so the electricity flows

  • and flows and flows without any resistance or diminution

  • and you get a strong magnetic field.

  • In order to build the technology to get a uniform 117,

  • 500 gauss magnetic field you need a kettle about this big

  • across and about this high

  • to house the super-conducting magnet and the liquid helium

  • and the shims and so forth and finally if you get

  • to say an 800 megahertz

  • and of course it's all linear proportionality you're going

  • to have a 188, 000 gauss magnetic field and that is close

  • to as big as can currently be made uniform

  • so now you'll have a magnet that's even bigger and needs

  • to have its own room in order to house it and flux lines

  • that go very far out and the limits

  • on commercial instruments these days are about 900 megahertz

  • and the thing costs, I guess ours cost about for

  • to whole thing about 2 and a half million dollars

  • at a time you're at 900 megahertz it's many,

  • many millions of dollars and there may be one,

  • I think one gigahertz out there but we really for now

  • at least seem to-- what?

  • >> In France or something.

  • >> I think so.

  • We really seem to have just pushed the limits of technology

  • for how much electricity you can put in a super-conducting coil

  • without it just ripping itself apart.

  • All right so the other quantity we have

  • in this equation is gamma.

  • Gamma is called the magnetogyric ratio sometimes you'll hear it

  • referred to as the gyromagnetic ratio.

  • This is a property of the individual nucleus.

  • The bigger the gyromagnetic ratio,

  • the bigger the magnetogyric ratio effectively the bigger the

  • nuclear spin, the bigger the magnet that the nucleus is.

  • Protons actually are good.

  • They have one of the biggest magnetogyric ratio

  • of any nuclei studied 26, 750 and it's 53.

  • What am I thinking here?

  • And so just to put this into context at 117,

  • 500 gauss in other words the relatively large magnet,

  • so at 117, 500 gauss you have the nuclei flips its spin

  • at 500 megahertz.

  • If we look at C 13 we get a gyromagnetic ratio of 6,

  • 728 and that corresponds to absorbing energy at a frequency

  • of 125.74 megahertz on this 117, 000 gauss magnet.

  • So one of the implications, remember I said you were dealing

  • with very small energy differences.

  • One of the implications is the energy differences are even

  • smaller for carbon than for proton

  • so now you're getting doubly damned for carbon

  • because the national abundance for C 13 is only 1.1 percent

  • so most of your carbons aren't even C 13.

  • Indeed with small molecules most

  • of your molecules don't even contain one C 13 in them.

  • We saw that in mass spec where you see the C 13 isotopomer peak

  • and for the small molecules that we were looking

  • at that peak is small compared to the C 13 isotopomer peak

  • but you're getting damned again

  • because its small magnetogyric ratio leads

  • to smaller energy absorption.

  • Now the other thing you have

  • to remember is even though you're recording your C 13 NMR

  • spectrum on a quote 500 megahertz NMR spectrometer

  • you're not reporting your carbon NMR on at 500 megahertz,

  • if you were you'd be that lucky person not in France but maybe

  • on Mars who has access to a two gigahertz NMR spectrometer

  • and there ain't no such animal right now.

  • All right fluorine 19 isn't so bad.

  • Its magnetogyric ratio is 25, 179 so that corresponds

  • on the same spectrometer to 470, 000, 470.58 megahertz.

  • Usually it takes certain types of probe technology.

  • We'll talk more about that later but certain types

  • of coil technology to tune to higher frequencies

  • and certain type of coil technology

  • to tune to lower frequencies.

  • So often if you want a really good proton NMR you will use a

  • special probe where the coil that's tuned for proton is inner

  • and close to the sample and the coil that's tuned

  • for other nuclei is bigger and further away from the sample.

  • That sort of probe won't be as good for carbon 13

  • because you have the coils further away from the sample,

  • the coil that's good for C 13.

  • Conversely, if you find

  • that Phil Dennison has put a broadband probe

  • in the spectrometer where the nucleus

  • at the lower frequency is inside in the coil you may find

  • that the proton NMR collects is not as good or is not

  • as sensitive or is not as sharp and well shimmed

  • because the coil is further out.

  • Fluorine is interesting because often you can use the same coil

  • for both fluorine and for proton.

  • Phosphorus also has a smaller magnetogyric ratio.

  • It's 10, 840.

  • Now remember fluorine and phosphorus have all

  • of their naturally occurring nuclei as F 19 and all

  • of their naturally occurring nuclei as P 31

  • so these are not damned

  • by the low isotopic abundance the way phosphorus is.

  • Another nucleus that's sometimes studied is deuterium.

  • Deuterium we talked about the nuclear quadrupole.

  • You also have your lock coil in there.

  • The magnetogyric ratio for deuterium is 4,107

  • so that means your lock frequency

  • on this spectrometer is at 76.76 megahertz.

  • [ Silence ]

  • [ Inaudible student question ]

  • So the cryoprobe technology is really wonderful.

  • What they've done

  • in the cryoprobe technology is they have cooled the probe

  • and it's either, I guess it's not a super-conducting probe

  • but what it is is a very low noise probe.

  • And because the electronics of the probe are cooled

  • so you don't get much electronic noise

  • and the result is it's very high sensitivity.

  • And we were fortunate that had just,

  • when we bought it they had just developed technology

  • that had both carbon and proton sensitivity

  • and basically special coil technology

  • so that instrument is super good for proton.

  • It's got a huge, just an incredible signal

  • to noise ratio, better than even the 800 megahertz spectrometer.

  • It's also super good for carbon.

  • I want to come back to these magnetogyric ratios

  • because you've seen this with your own eyes.

  • Now we already talked about the coupling, the J 1 CD coupling

  • in chloroform and remember I said you see this

  • one-to-one-to-one triplet in the C 13 NMR and the separation

  • of the lines is 32 hertz.

  • Well if you've ever looked hard at your chloroform peak

  • in the proton NMR, so here we have DC coupling,

  • our H2 coupling but if you ever looked hard

  • at the chloroform peak

  • in the proton NMR what you see is something like this.

  • You see a main peak for your CH

  • and of course what you're looking at is chloroform

  • but you'll also see two peaks here

  • that are the C 13 satellites and those correspond

  • so this is your C 12 peak and those correspond

  • to the J coupling to the C 13.

  • In other words what you're seeing here is a doublet

  • and the separation of those two lines is 209 hertz

  • and the mathematical relationship between 209

  • and 32 is the same as the mathematical relationship,

  • the ratio between 26,753 and 4107.

  • In other words it's 6.5,

  • in other words the magnetogyric ratio is 6.5 times bigger

  • for a proton than for a deuteron and we see

  • that directly in the J coupling.

  • The effect of the magnet that the deuterium has

  • in splitting the carbon is one-sixth point fifth the effect

  • that the carbon has in splitting the proton

  • because coupling is mutual.

  • All right the last thing I want to talk about I've talked

  • about how damned we are by energy being low.

  • I've talked in the case of carbon about isotopic abundance

  • but now the really damning thing ends

  • up being the Boltzmann distribution.

  • That is the population of the spin states.

  • In the case of a benzene all of your molecules are

  • in the ground electronic state.

  • In the case of a ketone all of your carbonyls are

  • in the ground vibrational state but in the case

  • of nuclei the energy difference between the alpha

  • and beta states is so small that both are populated

  • and if you think back to your P chem

  • and you calculate the number in the beta state

  • versus the alpha state that's going to correspond

  • to the difference in energy, delta E over KT

  • where K is the Boltzmann constant and then

  • if we just remember that delta E equals H NU is equal

  • to H times gamma times B naught over 2 pi and then we say,

  • okay let's just take at 70,500 gauss, that's our 300 megahertz

  • and let's plug in N beta divided by N alpha is equal to

  • and if I plug in that's E to the negative 6.63 times 10

  • to the negative 34 times the magnetogyric ratio 236753 times

  • 70,500 applied magnetic field over 2 pi divided

  • by our Planck's constant of 1.38 times 10 to the negative 23

  • and let's say we're saying at 298 Kelvin.

  • So I say 298 here and when I work that all

  • out what I get is this number comes

  • out to a quotient that's very, very, very close to one .999952.

  • Four nines and five two corresponds to the ratio

  • in the beta state over the ratio in the alpha state.

  • In other words we have 48 more protons out of two million,

  • so where all of your carbonyls are available to absorb a photon

  • because remember when you apply a photon it can either kick a

  • nucleus up from the ground state to the first

  • from the alpha state to the beta state or down

  • from the beta state to the alpha state.

  • So it's only that differential population, only that 48

  • out of two million that are available to absorb.

  • If we apply a higher magnetic field it only gets linearly

  • or almost linearly better.

  • At 117,500 gauss, remember that's our 500 megahertz then we

  • only get to an N beta over an N alpha,

  • in other words a relative population

  • of point again four nines, .999919.

  • In other words it only gets a little bit better.

  • It's only 81 protons out of two million.

  • So we are damned by the low energies.

  • We are damned by the low differences in population

  • and this is why NMR compared

  • to other spectroscopic techniques is very insensitive

  • and why it took a long time to develop.

  • Next time we'll talk about how this NMR spectrometer works,

  • how we absorb our energies and then how we translate

  • that into a spectrum and I'll also talk a little bit maybe

  • about some of the aspects of the spectrum. ------------------------------44553e5ef327--

>> All right what I'd like to do today and on Monday is to talk

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B2 中高級

化學203.有機光譜學。第07講。NMR光譜學介紹,第1部分。 (Chem 203. Organic Spectroscopy. Lecture 07. Introduction to NMR Spectroscopy, Part 1)

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    Cheng-Hong Liu 發佈於 2021 年 01 月 14 日
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