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>> So methyl groups and a methionine group.
And you'll really, even
with a very high field NMR spectrometer,
not going to be able to see a lot of distinction
between these structures.
But the big difference in mass spectrometry is
that fragmentation will occur at points that give you secondary
and tertiary carbocations more.
So if we look, for example, on the next spectrum,
on the spectrum of 4-methyl undecane, and now we look,
we see a break in this usual pattern, in other words the peak
at 71 is enhanced and the peak at 57 is diminished.
And the other thing that's interesting is for all
and intents and purposes, you don't see the molecular ion,
or it's very, very small.
And of course, the reason
for this is now you've got two desirable break points
in the molecule where cleavage
over here will give you a pentyl cation,
a secondary pentyl carbocation.
And that's going to give rise to your enhanced peak at 71.
And conversely, there are fewer ways to break this molecule
to give you a butyl carbocation
because undecane had two positions you could break,
whereas -- I'm sorry, dodecane had two positions you can break,
whereas methyl undecane has one.
So your peak at 57 is diminished.
And if you look hard, you'll see your peak
at 127 is also enhanced.
Right here you have this sort of downward curve.
So a person with a mass spectrometry --
with a mass spectrometer could look at this molecule
and say this is 4-methyl undecane rather than,
say, 5-methyl undecane.
And this becomes important in marine natural products
where often you get lipid type groups with unusual patterns
as well as in identifying lipid structures.
>> So when we talk, like we're [inaudible] fragmentation,
oftentimes we would try and favor to get [inaudible]
at secondary and tertiary positions?
>> Absolutely.
Absolutely.
>> Like they're in radical position, like, does it matter
if it's a primary [inaudible]?
>> Stabilization of the radical is less important
than stabilization of a carbocation.
Radicals are unhappy, carbocations are really unhappy.
Radicals have at least one electron in the vacant,
what's essentially a p orbital,
whereas carbocations have no electrons there.
So they're much more unhappy,
plus you have charge to stabilize it.
Other questions?
>> At the 71 and 127 fragmentations [inaudible]
migrate over to make the tertiary or [inaudible].
>> I would imagine, yeah, I would imagine you probably --
well, would the methyl.
There's no simple migration.
So if you look at a 2-pentenyl cation,
there's no simple migration that will give you rise.
I guess what you'd need is, yeah,
I don't know the answer to that.
I know in cyclohexane,
cyclohexyl carbocation chemistry,
if you can get a 1,2-hydride shift
that gives you a tertiary, yeah, it'll occur.
If you can get a 1,2-alkyl shift,
that'll give you a tertiary.
So yeah, I'd say if you can find a 1,2-methyl shift,
it will probably occur.
But in this case, I don't think there's one occurring.
And then by the time you go to a highly branched compound,
so here's an example where you really do only have --
you do see the tertiary peak predominating.
So here's another isomer, highly branched isomer.
And you'll notice the peak that predominates is absolutely
that tert-butyl carbocation.
And again, you don't see the M plus,
you don't see the molecular ion.
>> So when you're looking at a spectra like that,
how do you know that there's a peak there?
>> Aha. Great question.
So the first thing that people often do is blow up the region
where they suspect the molecular ion is.
Now, the second thing is,
let's say you have a little bit of information.
Remember the nitrogen rule that I mentioned,
the fact that in the EI mass spectrum,
if a compound has an odd number of nitrogens,
if it has 1 nitrogen or 3 nitrogens or 5 nitrogens,
the molecular weight is odd.
And that's just the math of making up molecules.
So, in this spectrum we were seeing peaks at 43,
peaks at 57, et cetera.
So, if you know, oh my molecule has no nitrogen,
and then you see only odd peaks, you say, oh wait a second,
these all have to be fragments.
So if you have some additional information,
for example you say, okay,
I know my compound is a marine natural product
that has no nitrogens it, but I'm only seeing a peak at 171,
in the EI mass spec -- and remember, it's all reversed
in the CI mass spec because you're putting on a proton,
which adds 1 -- then you'd say, okay,
that can't be the molecular ion.
And that's really important
because otherwise you've gotten yourself stuck
in this mindset saying, oh this is the molecular ion.
How do I get this structure?
All right, I want to talk for a moment about alkenes
and then move on to heteroatom compounds.
So alkanes are the most non-intuitive
because alkanes have no obvious place to take
that odd electron out.
We have to be thinking about sigma bonds
or molecular orbitals.
By the time we get to alkenes, we can say okay,
the highest occupied molecular orbital is a pi orbital.
We'll kick an electron out.
We'll get a radical cation.
And we really can remind ourselves that there are going
to be two resonance structures to it.
And the chemistry of alkenes is very similar to the chemistry
of alkanes, but now at least we sort
of have a way of thinking about it.
And we can think about things as a homolytic cleavage mechanism,
often to give an allylic carbocation.
So let me just write sort of a generic compound.
So imagine that we had an alkene over here.
And now I've taken the alkene
and I've generated the radical cation.
I've generated the molecular ion.
One of the very fundamental reactions
of radicals is homolytic cleavage.
Homolytic cleavage means you take this bond
and you break it equally.
Homo lytic.
You take one electron, you send it one way.
You take one electron, you send it the other way.
So I'll draw my little fishhook curved arrows
that you've been using, hopefully,
since sophomore organic chemistry
for this type of reaction.
And I'll take away minus R prime dot, so we don't see
that because that's a radical.
And this gives rise to an allylic cation.
And so the whole series of peaks --
The whole series of peaks that you might see for an alkane
with 43, 57, 61, you will see largely diminished by 2
for an alkene, 41, 55, et cetera, going up the series.
So in the case of alkanes, we were talking
about CNH2N plus 1 plus.
Here we're talking about CNH2N minus 1 plus.
Now, the alkene tends -- I'm not going to write it
out as a mechanism, but you can write a curved arrow mechanism
to walk your radical all over the molecule by a series
of 1,2-hydride shifts.
And so the alkene tends not to stay put.
So you can't -- you might think, oh I could tell
where the alkene is in the molecule,
but this migrates throughout the molecule.
So you can't pinpoint where the alkene is.
So let me just put up for comparison and contrast,
let me put up 1-dodecene.
That's on the flip side of your page.
Thank you.
And so for 1-dodecene, you see a peak at 41 by this new pathway
and ditto for 55, for 69 and so forth.
And of course, you do still see the 43 peak.
So you do also see the other pathway as well
as a 57 peak and so forth.
So the peak at 41, for example,
is simply this cleavage mechanism I talked about.
And I can at least write it as 1, 2, 3, 4, 5,
6, 7, 8, 9, 10, 11, 12.
I can write it, there are two resonance structures,
one with the primary positive charge
and the other the major contributor
with the secondary positive charge.
But I can write a curved arrow mechanism showing the homolytic
cleavage pathway to give rise to the allylic carbocation.
Woops.
Thoughts or questions at this point?
>> What are the peaks with the circles on top of them?
>> Peaks with the circles are other pathways that involve,
for example, loss of a hydrogen atom and so we're not --
we're not talking about --
we're not going to talk
about every absolutely every mechanism.
So for example, this peak at 42, although some of it comes
from the small amount of C13 isotopomer,
also has to correspond to a species that is a radical cation
with a formula of C3H6, but we're not going to talk
about the mechanism for formation.
All right.
I think at this point what I'd like to do is to move
on to heteroatom-containing compounds.
And what I think is neat
about heteroatom-containing compounds is we really can make
sense of their chemistry from just a few mechanisms.
So in addition to the homolytic cleavage, we can also think
of heterolytic cleavage mechanisms
and hydrogen abstraction fragmentation.
[ Writing on Board ]
All right.
So I'll write a generic heteroatom-containing compound
as R-Y showing a lone pair on Y. And I'm going
to be generic enough that I mean that this could be an alcohol,
an ether, a halide, an amine.
But also the OR group of an ester.
And so later on in the homework set you'll get esters
and we'll see mechanisms involving the carbonyl
and also mechanisms involving the OR group.
And we'll also say an amide NR2 group.
All right.
So the general gist is we can think of the molecular ion
as kicking out one of the electrons from the lone pair.
And so, for example,
we can envision a homolytic cleavage mechanism much
as we envisioned the homolytic cleavage in the case
of our alkenes or our -- well, our alkenes.
So we can envision a homolytic cleavage.
And let me enhance my molecule here.
So I'm drawing in the alpha carbon,
the carbon that's directly attached
to the heteroatom, and the beta carbon.
The carbon that's one over.
And imagine a mechanism just like we saw before
in the radical cation from the alkene where the bond one
over from the odd electron breaks, sending one electron
to form a double bond and the other electron
to the other carbon.
So in such a mechanism, we'll generate a radical.
And of course, the radical you won't see.
And we'll also generate a species with a double bond
to the Y group and a positive charge
on the Y group that we'll see.
The other mechanism we're going
to see is a heterolytic cleavage.
In a heterolytic cleavage mechanism,
that means the two electrons go in one direction.
Heterolytic cleavage, mixed cleavage.
In other words, the electrons don't go one
in one way, one in the other.
They both go in the same way.
And for simplicity, I'll just write our group like so.
So here we are back at our --
I won't need to write in the rest of the molecule.
So you can think of the Y group -- remember that's an oxygen
or a nitrogen or something with a positive charge --
you can think of it as a leaving group.
And the leaving group takes its electrons and leaves,
much as you've seen in regular carbocation --
regular cations that have radical cation chemistry,
where in an SN1 type reaction or an E1 reaction,
the first step is the leaving group leaves
with its pair of electrons.
And you get R plus.
You get a carbocation.
Now the other mechanism than can occur that's along the same
lines -- so another heterolytic cleavage mechanism is
after a hydrogen atom abstraction fragmentation,
you can end up with a proton on your leaving group.
And so I'll write this as R-Y-H with a positive charge on Y.
And in that case, again, you can take your electrons
and your leaving group can leave.
The third common mechanism
that you'll see is a hydrogen atom abstraction
fragmentation mechanism.
And the point that I'll make here is that in addition
to fragmenting, radicals also have a propensity
to pull off hydrogens to extract atoms.
It's one of the common reactions of radicals.
If you've already studied perhaps as an undergraduate,
tributyltin hydride chemistry, where you have maybe AIBN,
an initiator to generate a free radical
and a radical chain mechanism
and you used tributyltin hydride, one of the key steps
in your chain mechanism is going
to be the radical plucking off a hydrogen.
If you have a hydrogen in your molecule,
the radical can pluck off the hydrogen.
It's really quite indiscriminate about where it plucks it off.
Remember, not only is it a free radical,
but it's also a very hot free radical.
And so it can go ahead and pluck off that hydrogen
and it makes you feel like a freshman once again
where you have to keep track of, because you're seeing
so many unfamiliar species, you have to keep track
of your formal charges and keep track of your odd electrons.
And so now, we have a positive charge on Y.
And this can undergo further fragmentation either by way
of a homolytic cleavage over here.
So I'll say homolytic or by way
of a heterolytic cleavage over here.
[ Writing on Board ]
All right.
In the abstract, this sounds very, very complicated.
So what I'd like to do is to render it concrete.
And I have a handout.
Some transparencies.
[ Background Sounds ]
>> What this -- this is your homework.
I'm helping you.
Do you want me not to?
>> Help us.
>> Help you?
Yeah! But if you want, we can just leave now.
>> No.
>> No? All right.
What I'd like to do is to convince you
that these very few mechanisms I showed you actually account
for all the peaks.
So look. All right.
So here --
All right, the first think you'll notice
as that our compound has molecular weight of 102,
but our M plus is missing.
This is not uncommon for alcohols.
Then what you can think of is if you generate the radical cation
and you do a homolytic cleavage.
So we have a methyl, a hydrogen
and a butyl group attached to the alpha carbon.
If we cleave the hydrogen in a homolytic cleavage,
and you'll often see people do an abbreviated mechanisms
where they just write one fishhook.
Part and parcel with that, of course,
is this odd electron comes in over here and we lose hydrogen.
So if we do minus H dot like so, then -- and I'll tell you what.
I will even be a good person and write in all my lone pairs
of electrons to help you out.
Then that species is our species at 101.
So here we see a tiny peak at 101.
If I, in a very slavish fashion simply repeat this process --
And I'll just put the hydrogen down here.
Put my methyl over here.
If I, in a very slavish fashion repeat this process
and lose a methyl dot, a methyl radical, now I have 1, 2, 3, 4,
5, 6, and I should have --
woops, what am I doing wrong here?
1, 2, 3, 4, 5, 6 -- 1, 2, 3, 4, 5, 6.
I lost my hydrogen.
2, 3, -- did I add a carbon here?
Take off 1, 2, 3, 4, 5 oops.
I added in -- I added 7,
so easiest solution is just cut off the end here.
All right.
So I lose the methyl group and I end up with this species.
Should have 1, 2, 3, 4, 5.
So that explains our peak at 87.
It's loss of a methyl.
That's 87 over there.
If I do the same and I'm going to skip the mechanism,
but obviously if I just do minus butyl dot.
That's going to take us to protonated acetaldehyde.
And that's going to be our peak at 45.
All right.
So that actually takes care
of three different key peaks in the spectrum.
I'll show you one more pathway,
and that's our abstraction fragmentation pathway.
So if I go ahead, and again, I write our species.
And I'll just write it in a slightly different way just
to make it suggestive.
So, if I now write our species, the hydrogen,
the oxygen can pluck off a hydrogen.
So I'll draw a fishhook.
And a fishhook.
And just for the sake of not having fishhooks fly everywhere,
I won't draw a fishhook back to that carbon.
But you can if you like.
So I'll just draw the radical on that carbon.
And now there are a couple of ways that we can go.
If, for example, water leaves.
And at this point we have our heterolytic cleavage.
Water is leaving, taking its pair of electrons with it.
So I'll just put my pair of electrons onto water, like so.
So we get a radical cation over here.
That radical cation's going to be at 84.
In fact, it's very common to see minus 17 for an alcohol.
So that's a common cleavage pathway.
And if I further go ahead and lose a methyl radical,
and again, I'll draw a single fishhook, minus CH3 dot.
Now that's going to give rise to our, I think the last species
that we were supposed to see, which is our peak at 69.
So, go ahead.
>> Do you not have that heterolytic cleavage
where you just connect the [inaudible]?
>> Where?
>> That one right there.
Can you just have that as a --
>> The heterolytic cleave --
>> Yeah.
>> Okay. Beautiful, beautiful question.
So the question is can we also have loss of OH dot.
And the answer is you have a tiny amount over here.
Not enough to give a big peak.
But you actually anticipated my next remark.
And if we flip to the next spectrum --
so the problem is that the OH radical is really,
really unstable.
You have to have -- an oxygen has an incomplete octet.
And so that's bad.
But the other thing that's bad
about it is you get no hyperconjugative stabilization
of the radical.
Now, if we look at this ether here on the next page,
then you can see this mechanism.
So I'll just use this as a chance to show this to you.
So you also see a homolytic cleavage mechanism.
I'll leave that to you to write on your own.
And if we apply a heterolytic cleavage here,
the leaving group takes its two electrons and leaves.
So this radical,
this oxygen-centered radical is more stable
than a hydroxyl radical, so we lose 73.
Our molecule was 130 to start with.
We do see it.
But now we get a carbocation here that either
in a concerted fashion
or a step-wise fashion almost certainly rearranges
to the tert-butyl carbocation, which we see at 57.
And so the answer is
in the alcohol you may have a little bit of it,
but not enough to really see.
In this case, we have even more so we see it.
In some cases you'll see it directly with the alcohol.
So, I think -- yeah, in the alcohol, if you look,
there's a teeny tiny peak at 85.
And it's not clear whether it's big enough --
whether it's the C13 isotope or whether it is this.
All right.
I'll leave it to you.
We'll talk about the next one in discussion section,
but I want to finish up by talking
about carbonyl compounds, because we've gotten
but one key mechanism here.
And the key mechanism for carbonyl chemistry --
So, for carbonyl compounds, and that's the whole family,
the aldehydes, ketones, et cetera, esters, amides, acids.
[ Writing on Board ]
The whole bloody family.
You can think of this in a couple of ways.
You'll have a homolytic cleavage pathway.
And in the homolytic cleavage pathway,
it's the same as before.
You picture taking your electron out of a lone pair.
The reason is the lone pairs are the highest occupied molecular
orbitals in the molecule.
In a homolytic cleavage pathway, you break a bond like so.
You lose R dot, you lose a radical.
And you get an acylium ion -- in many cases --
so that'll cost you part of the molecule.
In many cases you'll see a further fragmentation
where you now have a heterolytic cleavage.
You lose carbon monoxide.
And you get -- I guess I've called this R prime.
So I will stick with that.
And you get R prime plus as a carbocation.
This same chemistry that occurs here can occur
in Friedel-Crafts solution phase chemistry.
So for example, if I set
out to do a Friedel-Crafts acylation reaction
with a compound that could easily fragment
to give a tert-butyl alkyl carbocation,
I might end up seeing Friedel-Crafts alkylation
competing with the Friedel-Crafts acylation.
In other words, loss of carbon monoxide from my acylium ion.
In the gas phase where molecules are hot,
it's even more prevalent.
The other key reaction
of carbonyl compounds is the McLafferty rearrangement.
That's a charge-accelerated retro ene reaction.
An ene reaction is a pericyclic reaction.
It's very much akin to the Diels-Alder reaction.
In the forward direction it brings together an alkene
component and a component with a double bond.
In the reverse direction you just push electrons
in the opposite way.
And I'll show you how I like to think
of the McLafferty rearrangement.
Sometimes you'll see it written with fishhooks.
You'll see it written as a radical reaction.
To me, this makes much more sense to think of it
as a pericyclic reaction.
So here, I've written a alkyl chain hanging off
of my radical cation.
And if we simply move electrons in a ring in pairs
in a 6-electron pericyclic process much like you're going
to learn in the Van Vranken class in 201
if you haven't already done so.
Now, you can get a very nice --
and I guess I'll call that R prime --
you can get a very nice curved arrow mechanism
that kicks out an alkene.
Take one moment to show you this pathway.
So you will see in this compound, you will see examples
of the homolytic cleavage, the homolytic cleavage
with loss of carbon monoxide.
I'll let you figure those all out.
But I just want to show you the McLafferty pathway.
Here we are at 1, 2, 3, 4, 5, 6 -- so 2-hexanone.
And if I just write my McLafferty rearrangement
like so, I lose propene, that's minus 42.
We started with a weight of 100,
and so let me just write my resulting product.
And so we come to a peak at 58.
And there we see our peak at 58.
So as I said, you will also see all these other pathways we've
talked about.
You'll see the homolytic cleavage and further loss
of CO. You'll see abstraction, fragmentation as well.
And I'll let you figure all of that out on the homework.
And I should point out on the preceding problem
on the amine problem, in addition to seeing the pathways
that we've talked about, in addition to seeing for example,
the homolytic cleavage pathway,
you will see a further retro ene pathway giving rise
to what actually is the strongest peak in the molecule.
So we'll talk more about these on Monday.
All right. ------------------------------77a982119737--