The minus 12 part at the bottom of the waveform, and I'll get a scope in a minute, remains at minus 12 volts and I think the idea of that is so that if, I don't know, your type 2 plug was lying in a pool of water and there just happened to be 2.7 K between Protective Earth and Control Pilot, it's unlikely but it could happen, seeing this asymmetry by virtue of this diode means that it's not going to turn the mains on when the connector is lying in a puddle. So now I've connected both resistors in parallel so that we're pulling the top half of the square wave down to 6 volts and it's turned the mains on. Let's turn off the supply to the EVSE so that that drops out and see if it's happy to see this situation immediately it powers on. Put the power on the EVSE, standby and yeah it goes straight into supplying power so the relays have closed and it's supplying mains power to the car so it doesn't seem to mind, there doesn't seem to be any kind of sequencing required, if the conditions are satisfied it just gets on and supplies power to the car. Now one thing I wanted to test, if I short out this diode with a crocodile clip cable then we're going to pull down both the top half of the square wave and the bottom half, will it detect that there is then symmetry on the pull down? No it doesn't, it doesn't seem to care whether the diodes... I'm not sure whether this crocodile clip is any good actually, perhaps I'll try another one. Well let's try this again in the connecting state so my second resistor is disconnected, let's see what happens if the diode is not there and no it doesn't seem to care about that, so it doesn't seem to be taking much notice of whether or not that diode's in circuit. I'll just get another croc clip because I can't be sure this is a good one. Right I've got a new crocodile clip lead, this one's got an S on it which means I've soldered the wire to the crocodile clip because the crimped ones can be quite bad and the little C there means that it's high current, I've got a decent piece of wire on there. So why isn't it going into... oh it's gone into end mode, oh that's interesting, yes but if I put the second resistor across there it immediately goes into charging mode. It's saying end rather than connecting which is slightly odd. Okay let's make it conduct and now short out this diode. No it doesn't seem to care whether or not the pull down on the square wave is symmetric or asymmetric. I think it's time to get a scope and have a look at the square wave on here. So here's my scope hooked up and I'm having to use this additional light here otherwise it bleaches out the screen of the scope, it's just an exposure compensation thing. I suppose I could do that on the camera but never mind I've done this now. So we can see that it's exactly one kilohertz, the width of the pulse is about 10% which is what you want for 6 amps, you can see 6 amps there and if I press the current button in this end state I can actually vary the current so 8 amps is more than 10% that's 10 amps, 13 amps and this one goes up to 16 amps. I can't remember the percentages just at the moment let me check. Right I've done the exposure compensation on the camera now. Oh it's not quite as good is it? How do I adjust that? No that's not working terribly well.
波形底部的負 12 部分(我馬上就會拿到一個示波器)保持在負 12 伏,我認為這樣做的目的是,如果,我不知道,你的 2 型插頭插在水池裡,而保護接地和控制引腳之間剛好有 2.7 千伏,這不太可能,但有可能發生,看到這個二極管的不對稱,意味著當連接器插在水池裡時,它不會接通市電。現在我把兩個電阻並聯起來,這樣就能把方波的上半部分拉低到 6 伏,從而接通電源。讓我們關閉 EVSE 的電源,使其斷電,看看它是否樂意看到這種情況,並立即接通電源。接通 EVSE 的電源,待機,然後它就直接開始供電,繼電器閉合,向汽