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  • - [Voiceover] So let's see if we can find

  • the derivative with respect to x,

  • with either x times the cosine of x.

  • And like always, pause this video

  • and give it a go on your own

  • before we work through it.

  • So when you look at this you might say,

  • "well, I know how to find

  • "the derivative with e to the x,"

  • that's infact just e to the x.

  • And let me write this down.

  • We know a few things.

  • We know the derivative with respect to x of

  • e to the x.

  • E to the x is e to the x.

  • We know how to find the derivative cosine of x.

  • The derivative with respect to x of cosine of x

  • is equal to negative sine of x.

  • But, how do we find the derivative of their product?

  • Well as you can imagine, this might involve

  • the product rule.

  • And let me just write down

  • the product rule generally first.

  • So if we take the derivative with respect to x

  • of the first expression in terms of x,

  • so this is, we could call this u of x times

  • another expression that involves x.

  • So u times v of x.

  • This is going to be equal to,

  • and I'm color-coding it so we can really

  • keep track of things.

  • This is going to be equal to the derivative

  • of the first expression.

  • So I could write that as u prime of x

  • times just the second expression not the derivative of it,

  • just the second expression.

  • So times v of x and then we have plus

  • the first expression, not its derivative,

  • just the first expression.

  • U of x times the derivative of the second expression.

  • Times the derivative of the second expression.

  • So the way you remember it is,

  • you have these two things here,

  • you're going to end up with two different terms.

  • In each of them, you're going to take

  • the derivative of one of them, but not the other one,

  • and then the other one you'll take the derivative of

  • the other one, but not the first one.

  • So, the derivative of u times v is u prime times v,

  • plus u times v prime.

  • When you just look at it like that,

  • it seems a little bit abstract and

  • that might even be a little bit confusing,

  • but that's why we have a tangible example here

  • and I color-coded intentionally.

  • We could say that u of x is equal to e to the x.

  • And v of x is equal to the cosine of x.

  • So v of x is equal to cosine of x.

  • And if u of x is equal to e to the x,

  • we know that the derivative of that

  • with respect to x is still e to the x.

  • That's one of the most magical things in mathematics.

  • One of the things that makes e so special.

  • So u prime of x is still equal to e to the x.

  • And v prime of x,

  • we know as negative sine of x.

  • Negative sine of x, and so,

  • what's this going to be equal to?

  • This is going to be equal to

  • the derivative of the first expression.

  • So, the derivative of e to the x which is just,

  • e to the x, times the second expression,

  • not taking it's derivative, so times cosine of x.

  • Plus the first expression,

  • not taking its derivative, so e to the x,

  • times the derivative of the second expression.

  • So, times the derivative of cosine of x

  • which is negative sine.

  • Negative sine of x.

  • And it might be a little bit confusing,

  • because e to the x is its own derivative.

  • This right over here, you can view this as

  • this was the derivative as e to the x

  • which happens to be e to the x.

  • That's what's exciting about that expression,

  • or that function.

  • And then this is just e to the x without taking

  • it's derivative - they are of course, the same thing.

  • But anyway, now we can just simplify it.

  • This is going to be equal to...

  • We could write either as e to the x times cosine of x,

  • times cosine of x minus e to the x.

  • E to the x times sine of x.

  • Times sine of x.

  • Or, if you want, you could factor out

  • an e to the x.

  • This is the same thing as

  • e to the x times cosine of x minus sine of x.

  • Cosine of x minus sine of x.

  • So hopefully this makes the product rule

  • a little bit more tangible.

  • And once you have this in your tool belt,

  • there's a whole broader class of functions

  • and expressions that we can start to differentiate.

- [Voiceover] So let's see if we can find

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B1 中級 美國腔

09-1(Product rule example)

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    yukang920108 發佈於 2022 年 07 月 12 日
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