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  • So let's think about how we could

  • find the slope of the tangent line

  • to this curve right over here, so what

  • I have drawn in red, at the point x equals a.

  • And we've already seen this with the definition

  • of the derivative.

  • We could try to find a general function that gives us

  • the slope of the tangent line at any point.

  • So let's say we have some arbitrary point.

  • Let me define some arbitrary point x right over here.

  • Then this would be the point x comma f of x.

  • And then we could take some x plus h.

  • So let's say that this right over here is the point

  • x plus h.

  • And so this point would be x plus h, f of x plus h.

  • We can find the slope of the secant line that

  • goes between these two points.

  • So that would be your change in your vertical,

  • which would be f of x plus h minus f

  • of x, over the change in the horizontal, which

  • would be x plus h minus x.

  • And these two x's cancel.

  • So this would be the slope of this secant line.

  • And then if we want to find the slope of the tangent line at x,

  • we would just take the limit of this expression

  • as h approaches 0.

  • As h approaches 0, this point moves towards x.

  • And that slope of the secant line between these two

  • is going to approximate the slope of the tangent line at x.

  • And so this right over here, this we would say

  • is equal to f prime of x.

  • This is still a function of x.

  • You give me an arbitrary x where the derivative is defined.

  • I'm going to plug it into this, whatever this ends up being.

  • It might be some nice, clean algebraic expression.

  • Then I'm going to give you a number.

  • So for example, if you wanted to find--

  • you could calculate this somehow.

  • Or you could even leave it in this form.

  • And then if you wanted f prime of a,

  • you would just substitute a into your function definition.

  • And you would say, well, that's going

  • to be the limit as h approaches 0 of-- every place you see

  • an x, replace it with an a. f of-- I'll

  • stay in this color for now-- blank plus h minus f of blank,

  • all of that over h.

  • And I left those blanks so I could write the a in red.

  • Notice, every place where I had an x before, it's now an a.

  • So this is the derivative evaluated at a.

  • So this is one way to find the slope of the tangent line

  • when x equals a.

  • Another way-- and this is often used

  • as the alternate form of the derivative--

  • would be to do it directly.

  • So this is the point a comma f of a.

  • Let's just take another arbitrary point someplace.

  • So let's say this is the value x.

  • This point right over here on the function would be x comma

  • f of x.

  • And so what's the slope of the secant line between these two

  • points?

  • Well, it would be change in the vertical, which

  • would be f of x minus f of a, over change in the horizontal,

  • over x minus a.

  • Actually, let me do that in that purple color.

  • Over x minus a.

  • Now, how could we get a better and better approximation

  • for the slope of the tangent line here?

  • Well, we could take the limit as x approaches a.

  • As x gets closer and closer and closer to a,

  • the secant line slope is going to better and better

  • and better approximate the slope of the tangent line,

  • this tangent line that I have in red here.

  • So we would want to take the limit as x approaches a here.

  • Either way, we're doing the exact same thing.

  • We have an expression for the slope of a secant line.

  • And then we're bringing those x values of those points

  • closer and closer together.

  • So the slopes of those secant lines better and better

  • and better approximate that slope of the tangent line.

  • And at the limit, it does become the slope of the tangent line.

  • That is the definition of the derivative.

  • So this is the more standard definition of a derivative.

  • It would give you your derivative as a function of x.

  • And then you can then input your particular value of x.

  • Or you could use the alternate form of the derivative.

  • If you know that, hey, look, I'm just

  • looking to find the derivative exactly at a.

  • I don't need a general function of f.

  • Then you could do this.

  • But they're doing the same thing.

So let's think about how we could

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B1 中級 美國腔

02-2 衍生物的形式和替代形式(Formal and alternate form of the derivative | Differential Calculus | Khan Academy)

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    yukang920108 發佈於 2022 年 07 月 12 日
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