as theta approaches zero of one minus cosine theta

over two sine squared theta.

And like always, pause the video and see if you

could work through this.

Alright, well our first temptation is to say,

"Well, this is going to be the same thing

"as the limit of one minus cosine theta

"as X approaches, or not X,

"as theta approaches zero.

"of theta, as theta approaches zero,

"over the limit,

"as theta approaches zero

"of two sine squared theta."

Now, both of these expressions

which could be used to define a function,

that they'd be continuous if you graph them.

They'd be continuous at theta equals zero,

so the limit is going to be the same thing,

as just evaluating them at theta equals zero

So this is going to be equal to one minus cosine of zero

over two sine squared of zero.

Now, cosine of zero is one and then one minus one is zero,

and sine of zero is zero, and you square it,

You still got zero and you multiply times two,

you still got zero.

So you got zero over zero.

So once again, we have that indeterminate form.

And once again, this indeterminate form

when you have zero over zero, doesn't mean to give up,

it doesn't mean that the limit doesn't exist.

It just means, well maybe

there's some other approaches here to work on.

If you got some non-zero number divided by zero,

then you say, okay that limit doesn't exist

and you would say, well you just say it doesn't exist.

But let's see what we can do to maybe, to maybe think

about this expression in a different way.

So if we said,

so let's just say that this,

let me use some other colors here.

Let's say that this right over here

is F of X.

So, F of X is equal to one minus cosine theta

over two sine squared theta,

and let's see if we can rewrite it in some way

that at least the limit as theta approaches zero

isn't going to, we're not gonna get the same

zero over zero.

Well, we can, we got some trig functions here,

so maybe we can use some of our trig identities

to simplify this.

And the one that jumps out at me

is that we have the sine squared of theta

and we know from the Pythagorean, Pythagorean Identity

in Trigonometry, it comes straight out of the unit circle

definition of sine and cosine.

We know that, we know that sine squared theta

plus cosine squared theta is equal to one

or, we know that sine squared theta

is one minus cosine squared theta.

One minus cosine squared theta.

So we could rewrite this.

This is equal to one minus cosine theta

over two times one minus cosine squared theta.

Now, this is one minus cosine theta.

This is a one minus cosine squared theta,

so it's not completely obvious yet

of how you can simplify it,

until you realize that this could be viewed

as a difference of squares.

If you view this as,

if you view this as A squared minus B squared,

we know that this can be factored as A plus B

times A minus B.

So I could rewrite this.

This is equal to one minus cosine theta

over two times,

I could write this as one plus cosine theta

times one minus cosine theta.

One plus cosine theta times one minus, one minus

cosine theta.

And now this is interesting.

I have one minus cosine theta

in the numerator and I have a one minus cosine theta

in the denominator.

Now we might be tempted to say,

"Oh, let's just cross that out with that

"and we would get, we would simplify it

"and get F of X is equal to one over

"and we could distribute this two now."

We could say, "Two plus two cosine theta."

We could say,

"Well, aren't these the same thing?"

And we would be almost right,

because F of X, this one right over here,

this, this is defined

this right over here is defined

when theta is equal to zero,

while this one is not defined when theta

is equal to zero.

When theta is equal to zero,

you have a zero in the denominator.

And so what we need to do in order

for this F of X or in order

to be, for this to be the same thing,

we have to say, theta cannot be equal to zero.

But now let's think about the limit again.

Essentially, what we want to do is we want to find

the limit as theta approaches zero

of F of X.

And we can't just do direct substitution

into, if we do, if we really take this seriously,

'cause we're gonna like,

"Oh well, if I try to put zero here,

"it says theta cannot be equal to zero

"F of X is not defined at zero."

This expression is defined at zero

but this tells me,

"Well, I really shouldn't apply zero to this function."

But we know that if we can find another function

that is defined, that is the exact same thing as

F of X except at zero,

and it is continuous at zero.

And so we could say,

"G of X is equal to one over two plus two

"cosine theta."

Well then we know this limit is going to be the

exact same thing as the limit

of G of X, as theta approaches zero.

Once again, these two functions

are identical except F of X is not defined

at theta equals zero,

while G of X is.

But the limits as theta approaches zero

are going to be the same.

And we've seen that in previous videos.

And I know what a lot of you are thinking.

Sal, this seems like a very, you know,

why don't I just, you know, do this algebra here.

Cross these things out of this.

Substitute zero for theta.

Well you could do that and you would get the answer,

but you need to be clear if, or it's important

to be mathematically clear of what you are doing.

If you do that, if you just crossed these two out

and all of a sudden you're expression

becomes defined at zero,

you are now dealing with a different expression

or a different function definition.

So to be clear, if you want to say this is the function

you're finding the limit of,

you have to put this constraint in

to make sure it has the exact same domain.

But lucky for us, we can say,

if we've had another, another function that's continuous

at that point that doesn't have that gap there,

that doesn't have that point discontinuity out,

the limits are going to be equivalent.

So the limit as theta approaches zero of G of X,

well, that's just going to be

since it's continuous at zero.

We could say that's just going to be,

we can just substitute.

That's going to be equal to G of zero

which is equal to one over two plus

cosine two, one over two plus two times cosine

of zero.

Cosine of zero is one,

so it's just one over two plus two,

which is equal to,

deserve a little bit of a drum roll here.

Which is equal to one fourth.

And we are done.