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- [Instructor] Let's say that we have the function g of x,
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and it is equal to the definite integral from 19 to x
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of the cube root of t dt.
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And what I'm curious about finding
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or trying to figure out is, what is g prime of 27?
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What is that equal to?
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Pause this video and try to think about it,
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and I'll give you a little bit of a hint.
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Think about the second fundamental theorem of calculus.
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All right, now let's work on this together.
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So we wanna figure out what g prime,
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we could try to figure out what g prime of x is,
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and then evaluate that at 27,
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and the best way that I can think about doing that
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is by taking the derivative of both sides of this equation.
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So let's take the derivative of both sides of that equation.
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So the left-hand side, we'll take the derivative
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with respect to x of g of x,
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and the right-hand side, the derivative with respect to x
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of all of this business.
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Now, the left-hand side is pretty straight forward.
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The derivative with respect to x of g of x,
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that's just going to be g prime of x,
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but what is the right-hand side going to be equal to?
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Well, that's where the second fundamental theorem
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of calculus is useful.
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I'll write it right over here.
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Second fundamental, I'll abbreviate a little bit,
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theorem of calculus.
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It tells us, let's say we have some function capital F of x,
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and it's equal to the definite integral from a,
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sum constant a to x of lowercase f of t dt.
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The second fundamental theorem of calculus tells us
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that if our lowercase f,
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if lowercase f is continuous on the interval from a to x,
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so I'll write it this way,
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on the closed interval from a to x,
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then the derivative of our capital f of x,
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so capital F prime of x is just going to be equal
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to our inner function f evaluated at x instead of t
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is going to become lowercase f of x.
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Now, I know when you first saw this,
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you thought that, "Hey, this might be some cryptic thing
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"that you might not use too often."
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Well, we're gonna see that it's actually very, very useful
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and even in the future, and some of you might already know,
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there's multiple ways to try
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to think about a definite integral like this,
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and you'll learn it in the future.
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But this can be extremely simplifying,
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especially if you have a hairy definite integral like this,
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and so this just tells us, hey, look, the derivative
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with respect to x of all of this business,
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first we have to check that our inner function,
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which would be analogous to our lowercase f here,
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is this continuous on the interval from 19 to x?
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Well, no matter what x is,
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this is going to be continuous over that interval,
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because this is continuous for all x's,
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and so we meet this first condition or our major condition,
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and so then we can just say, all right,
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then the derivative of all of this
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is just going to be this inner function replacing t with x.
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So we're going to get the cube root,
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instead of the cube root of t,
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you're gonna get the cube root of x.
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And so we can go back to our original question,
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what is g prime of 27 going to be equal to?
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Well, it's going to be equal to the cube root of 27,
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which is of course equal to three, and we're done.