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  • - [Voiceover] In a previous video we used the quotient rule

  • in order to find the derivatives

  • of tangent of x and cotangnet of x.

  • And what I what to do in this video is to keep going

  • and find the derivatives of secant of x and cosecant of x.

  • So let's start with secant of x.

  • The derivative with respect to x of secant of x.

  • Well, secant of x is the same thing as

  • so we're going to find the derivative with respect to x

  • of secant of x is the same thing as

  • one over,

  • one over the cosine of x.

  • And that's just the definition of secant.

  • And there's multiple ways you could do this.

  • When you learn the chain rule,

  • that actually might be a more natural thing to use

  • to evaluate the derivative here.

  • But we know the quotient rule,

  • so we will apply the quotient rule here.

  • And it's no coincidence that you get to the same answer.

  • The quotient rule actually can be derived

  • based on the chain rule and the product rule.

  • But I won't keep going into that.

  • Let's just apply the quotient rule right over here.

  • So this derivative is going to be equal to,

  • it's going to be equal to the derivative of the top.

  • Well, what's the derivative of one with respect to x?

  • Well, that's just zero.

  • Times the function on the bottom.

  • So, times cosine of x.

  • Cosine of x.

  • Minus,

  • minus the function on the top.

  • Well, that's just one.

  • Times the derivative on the bottom.

  • Well, the derivative on the bottom is,

  • the derivative of cosine of x is negative sine of x.

  • So we could put the sine of x there.

  • But it's negative sine of x,

  • so you have a minus and it'll be a negative,

  • so we can just make that a positive.

  • And then all of that over the function

  • on the bottom squared.

  • So, cosine of x, squared.

  • And so zero times cosine of x,

  • that is just zero.

  • And so all we are left with is sine of x

  • over cosine of x squared.

  • And there's multiple ways that you could rewrite this

  • if you like.

  • You could say that this is same thing as sine of x

  • over cosine of x times one over cosine of x.

  • And of course this is tangent of x,

  • times secant of x.

  • Secant of x.

  • So you could say derivative of secant of x is

  • sine of x over cosine-squared of x.

  • Or it is tangent of x times the secant of x.

  • So now let's do cosecant.

  • So the derivative with respect to x of cosecant of x.

  • Well, that's the same thing as the derivative

  • with respect to x of one over sine of x.

  • Cosecant is one over sine of x.

  • I remember that because you think it's cosecant.

  • Maybe it's the reciprocal of cosine, but it's not.

  • It's the opposite of what you would expect.

  • Cosine's reciprocal isn't cosecant, it is secant.

  • Once again, opposite of what you would expect.

  • That starts with an s, this starts with a c.

  • That starts with a c, that starts with an s.

  • It's just way it happened to be defined.

  • But anyway, let's just evaluate this.

  • Once again, we'll do the quotient rule,

  • but you could also do this using the chain rule.

  • So it's going to be

  • the derivative of the expression on top, which is zero,

  • times the expression on the bottom, which is sine of x.

  • Sine of x.

  • Minus the expression on top, which is just one.

  • Times the derivative of the expression on the bottom,

  • which is cosine of x.

  • All of that over the expression on the bottom squared.

  • Sine-squared of x.

  • That's zero.

  • So we get negative cosine of x

  • over sine-squared of x.

  • So that's one way to think about it.

  • Or if you like, you could do this,

  • the same thing we did over here,

  • this is the same thing as negative cosine of x

  • over sine of x, times one over sine of x.

  • And this is negative cotangent of x.

  • Negative cotangent of x, times,

  • maybe I'll write it this way,

  • times one over sine of x is cosecant of x.

  • Cosecant of x.

  • So, which ever one you find more useful.

- [Voiceover] In a previous video we used the quotient rule

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12-2(Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy)

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    yukang920108 發佈於 2022 年 07 月 12 日
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